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gayaneshka [121]
2 years ago
9

PLEASE HELP

Mathematics
2 answers:
Kazeer [188]2 years ago
7 0
$15. Lisa has $5. 5 + x = 20, so x=15
kotegsom [21]2 years ago
5 0

Answer:

15$

Step-by-step explanation:

I'm guessing theres only one friend based on the singular "friend" but if there was more please tell me

so we can do 5-20 = 15 and that 15 is what her friend had.

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How do u solve 4(3x-1)=9-x
Nastasia [14]

Answer:

x = 1

Step-by-step explanation:

Well the first step is to apply the distributive property:

4(3x - 1) is equal to (12x - 4). You DISTRIBUTE a '4' to what is inside the parentheses.

And btw, to make it easier, you can make 9 - x so that x is first. For example, (-x + 9). They're both the same thing, just written differently.

Your new equation is 12x - 4 = -x + 9. You want to now solve the equation.

Add the (-x) to both sides. It cancels out on the right side and you add it to 12x on the left side.

[If there's no number in front of a variable, you can always just put 1 in order to make it easier]

12x + 1x = 13x. Your new equation is 13x - 4 = 9. This should look very familiar. You simply add 4 to both sides. 9 + 4 = 13

Finally, 13x = 13. Divide 13 ÷ 13 to get 1.

x = 1

5 0
3 years ago
Which of the following sequences are not geometric? (check all that apply) a. 2,10,50,250,1250 b. 1,4,9,16,25,36 c. -4,-2,-1,-0.
Romashka [77]
A is geometric because each number is multiplied by 5.

B is not geometric because it is an arithmetic sequence. 

C is a geometric sequence because each number is divided by 2.

D is neither geometric not arithmetic because there is no common ratio and there is not a pattern being added or subtracted to each number.

So, your answer should be B and D.
8 0
3 years ago
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
What is 1, 852 in expanded form
OverLord2011 [107]
Expanded form is just each place value split into addition.

so 1,852 is
1000 + 800 + 50 + 2

that's all
5 0
3 years ago
Read 2 more answers
Find the GCF of the numbers using lists of factors.<br> 27,45<br> 30,48<br> 28,48,64
Svetach [21]

Answer:

1.) 6

2.)6

3,)4

Step-by-step explanation:

I think these are the gcf of the numbers

6 0
3 years ago
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