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FromTheMoon [43]
3 years ago
9

Talking about what might be a on with your study group in not good idea everyone will think different topics are

Mathematics
1 answer:
SashulF [63]3 years ago
5 0

different                                     345678ijhgfcvbnmkjhgfvbnvcdrtyuhjt56yuh                                              

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A crab crawls 7ft below sea level. Directly above the crab a bird flies 15 ft above sea level what is the distance between the c
adoni [48]
The crab crawls 7ft below (-7) and the bird flies ft above (15) so the distance between 15 and -7 is 22
4 0
3 years ago
Read 2 more answers
You are renting a moving truck for a day. There is a daily fee of $20 and a charge of 0.75 per mile. Your budget allows a maximu
Julli [10]

65-20 = 45

45/.75 = 60 miles

I hope this isn't to vague


6 0
3 years ago
Solve the following equation for y, and then identify the slope of the line: 9x-3y=15
sashaice [31]
9x-3y=15\ \ \ | subtract\ 9x\\\\
-3y=-9x+15\ \ \ | divide\ by\ -3\\\\
y=3x-5\\\\
y=ax+b\ \ a-\ slope\\\\
a=3\\\\Slope\ is\ equal\ to\ 3.
5 0
3 years ago
Read 2 more answers
van someone please help me with this i dont need an explaination i just need a. b. c. or d. please and thank you
Talja [164]

Answer:

option C

f(x)=-\sqrt{x+3}+8

Step-by-step explanation:

we have

f(x)=-2\sqrt{x-3}+8

using a graphing tool

see the attached figure N1

The range is the interval--------> (-∞,8]

y\leq 8

case A) f(x)=\sqrt{x-3}-8

using a graphing tool

The range is the interval--------> [-8,∞)

y\geq -8

case B) f(x)=\sqrt{x-3}+8

using a graphing tool

The range is the interval--------> [8,∞)

y\geq 8

case C) f(x)=-\sqrt{x+3}+8

using a graphing tool

The range is the interval--------> (-∞,8]

y\leq 8

case D) f(x)=-\sqrt{x-3}-8

using a graphing tool

The range is the interval--------> (-∞,-8]

y\leq -8

5 0
3 years ago
Find the value of the trigonometric ratio. Simplify the ratio if possible.
sweet [91]

Step-by-step explanation:

Given that,

BC = 8

Ac = 15

We can find AB using the pythagoas theorem.

AB=\sqrt{AC^2+BC^2}\\\\=\sqrt{15^2+8^2}\\\\AB=17

We know that,

\cos\theta=\dfrac{B}{H}, B is base and H is Hypotenuse

\cosB=\dfrac{8}{17}

Hence, this is the required solution.

3 0
2 years ago
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