Answer: 219.52 inch^2
Step-by-step explanation:
Given the dimensions of rectangular papaerboard:
Length = 20inches
Width = 16inches
Area of rectangle = Length × width
Area of rectangle = 20 × 16 = 320 in^2
Area of a circle = pi*r^2
Therefore, area of semicircle = (pi*r^2) / 2
Diameter of circle = width of rectangle = 16 inches
Radius = diameter / 2 = 16 /2 = 8inches
Therefore, area of semicircle = (pi*8^2) / 2
= (3.14 × 64) / 2
= 200.96 / 2
= 100.48 inch^2
Therefore, area of paperboard left :
Area of rectangle - area of semicircle
320 - 100.48
= 219.52 inch^2
Here it is given that the triangles ABP and DCR are similars, therefore we use the ratio rule which states that
corresponding sides of similar triangles are in same proprtion .
that gives
7/10 = BP/11
7*11=10BP
BP=7.7
Again using the ratio rule
7/10 = AP/6
42 = 10AP
AP = 4.2
Perimeter= AB+BP+AP = 7+7.7+4.2 = 18.9
Correct option is A.