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Eduardwww [97]
3 years ago
9

A rectangular paperboard measuring 20in long and 16in wide has a semicircle cut out of it, as shown below.Find the area of the p

aperboard that remains. Use the value 3.14 for pi, and do not round your answer. Be sure to include the correct unit in your answer.

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer: 219.52 inch^2

Step-by-step explanation:

Given the dimensions of rectangular papaerboard:

Length = 20inches

Width = 16inches

Area of rectangle = Length × width

Area of rectangle = 20 × 16 = 320 in^2

Area of a circle = pi*r^2

Therefore, area of semicircle = (pi*r^2) / 2

Diameter of circle = width of rectangle = 16 inches

Radius = diameter / 2 = 16 /2 = 8inches

Therefore, area of semicircle = (pi*8^2) / 2

= (3.14 × 64) / 2

= 200.96 / 2

= 100.48 inch^2

Therefore, area of paperboard left :

Area of rectangle - area of semicircle

320 - 100.48

= 219.52 inch^2

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General Formulas and Concepts:

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Order of Operations: BPEMDAS

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Step-by-step explanation:

<u>Step 1: Define equation</u>

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                     3x - 6 = 2x + 2
  2. Subtract 2x on both sides:          x - 6 = 2
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<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    3(8 - 2) = 2(8 + 1)
  2. Subtract/Add:                      3(6) = 2(9)
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Here we see that 18 does indeed equal 18.

∴ x = 8 is a solution to the equation.

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