Answer:
A: 5/18
B. 17/36
Step-by-step explanation:
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Event A: It is observed that there are 10 cases where the sum is greater than 8.
The cases are, (3,6), (4,5), (4,6), (5,4), (5,5), (5,6), (6,3), (6,4), (6,5), (6,6).
Thus, the probability for event A is ![\frac{10}{36}=\frac{5}{18}.](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B36%7D%3D%5Cfrac%7B5%7D%7B18%7D.)
Event B: The sum is not divisible by 3 and not divisible by 5.
There are 17 where the sum is not divisible by 3 and not divisible by 5.
The cases are, (1,1), (1,3), (1,6), (2,2), (2,5), (2,6), (3,1), (3,4), (3,5), (4,3), (4,4), (5,2), (5,3), (5,6), (6,1), (6,2), (6,5).
Thus, the probability for event B is
.
hope this helps:)