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ryzh [129]
3 years ago
12

How do I write 3/4 and 1/6 as a complex fraction

Mathematics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

\boxed{  \frac{3}{4} =  \frac{ \frac{3}{1} }{ \frac{4}{1} }  \to \: as \: a \: complex \: fraction} \\ and \\  \boxed{  \frac{1}{6} =  \frac{ \frac{12}{12} }{ \frac{18}{3} }  \to \: as \: a \: complex \: fraction}

Step-by-step explanation:

since \:  \frac{ \frac{1}{2} }{2}  \: is \: a \: complex \: fraction \\ then \: to \: convert \: 3/4  \: and  \: 1/6  \:  \\ to \: complex \: fraction \to \\  \frac{3}{4}  =  \frac{ \frac{3}{1} }{4}   \\ \boxed{  \frac{3}{4} =  \frac{ \frac{3}{1} }{ \frac{4}{1} }  \to \: as \: a \: complex \: fraction} \\  \frac{1}{6}  =  \frac{ \frac{12}{12} }{ \frac{18}{3} }  =  \frac{12}{12}  \div  \frac{18}{3}  = 1 \div 6 =  \frac{1}{6}  \\ \boxed{  \frac{1}{6} =  \frac{ \frac{12}{12} }{ \frac{18}{3} }  \to \: as \: a \: complex \: fraction}

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Y = -2/3x + 5....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we flip the slope and change the sign. So our perpendicular line will have a slope of 3/2 (see how I flipped -2/3 making it -3/2....and then changed the sign, making it 3/2)

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now we sub and find b, the y int
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so ur perpendicular equation is : y = 3/2x - 11 <==
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