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lys-0071 [83]
2 years ago
8

Los pasos para hacerlo

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
3 0
10.34 would be the answer
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If m∠ACD = 136° and m∠B = 42°, Find m∠A.
miss Akunina [59]

Answer:

2°

Step-by-step explanation:

Hello

I see you are very confused by this problem. However, there is an easy way to solve this one.

It has been proved that the sum of all angles in a rectangle is always 180°. Here is a way to prove it:

x y

_______A_________

/\

/ \

/ \

/ \

___/_______ \__

B C

we have two parellel lines xy and BC. It is true that:

xAy = 180°

xAB + BAC + CAy = xAy = 180

xAB = ABC

CAy= ACB

=> ........

I'll let you finish with your great intellect ^_^

HOPE YOU LEARN WITH JOY AND GOOD GRADE

3 0
3 years ago
What is simplest form of 13/26
Paul [167]
1/2 is simplest form.
Both 13 and 26 are factors of 13.
13 times 1 is 13 and 13 times 2 is 26.
So 13/26 = 1/2.

6 0
2 years ago
Sally invests $10,500 in an account that earns 6% annual simple interest. Assuming she makes no additional deposits or withdrawa
Fittoniya [83]

Answer: $2520

Step-by-step explanation:

The simple Interest earned on a deposit of P that has a rate of r% and a period of t years can be calculated by using the formula:

(P × R × T)/100

where P is principal

R is rate

T is time

P=$10,500

R=6%

T=4 years

Therefore:

Interest= (10500 × 6 × 4)/100

= 252000/100

= 2520

Sally will earn $2520 as interest after 4 years.

6 0
2 years ago
Does anyone know this, pls?
yan [13]

Answer:

Addition property of equality

Explanation:

You are adding 7 to both sides

Hope this helps!

8 0
2 years ago
Read 2 more answers
Simplify: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B5%7D-%5Csqrt%7B7%7D%2B%5Csqrt%7B12%7D%7D" id="TexFormula1
Masja [62]

Make use of the difference of squares identity,

a^2-b^2=(a-b)(a+b)

Let a=\sqrt5-\sqrt7 and b=\sqrt{12}. Then

\dfrac1{(\sqrt5-\sqrt7)+\sqrt{12}}\cdot\dfrac{(\sqrt5-\sqrt7)-\sqrt{12}}{(\sqrt5-\sqrt7)-\sqrt{12}}=\dfrac{(\sqrt5-\sqrt7)-\sqrt{12}}{(\sqrt5-\sqrt7)^2-(\sqrt{12})^2}=\dfrac{\sqrt5-\sqrt7-\sqrt{12}}{5-2\sqrt{35}+7-12}=-\dfrac{\sqrt5-\sqrt7-\sqrt{12}}{2\sqrt{35}}

Now multiply the numerator and denominator by √(35):

-\dfrac{\sqrt5-\sqrt7-\sqrt{12}}{2\sqrt{35}}\cdot\dfrac{\sqrt{35}}{\sqrt{35}}=-\dfrac{(\sqrt5-\sqrt7-\sqrt{12})\sqrt{35}}{70}=-\dfrac{5\sqrt7-7\sqrt5-2\sqrt{105}}{70}

8 0
3 years ago
Read 2 more answers
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