Step-by-step explanation:
Given an expression that represents a submarine that began at a depth of 15 feet below sea level and ascended at a rate of feet per minute is as follows :
-320+15y
We need to find the depth of submarine after 15 minutes.
Put y = 15 in the above expression.
-320+15y = -320+15(15)
= -320 + 225
= -95
Hence, the submarine is below sea level at 95 feet.
// Solve equation [1] for the variable x
[1] x = 2y - 1
// Plug this in for variable x in equation [2]
[2] 2•(2y-1) - 5y = -3
[2] - y = -1
// Solve equation [2] for the variable y
[2] y = 1
// By now we know this much :
x = 2y-1
y = 1
// Use the y value to solve for x
x = 2(1)-1 = 1
Answer:
Interquartile Range: 21.549999999999997 = 21.55
Step-by-step explanation:
