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4 years ago

How do hydraulics work?

2 answers:

4 0

I dont know if its right but
The basic rule of using hydraulic power is Pascal's Principle. Pascal's Principle: pressure exerted on a fluid is distributed equally throughout the fluid.Hydraulics uses incompresible liquids so the applied pressure from one end is equal to the desired pressure on the other end

Nana76 [90]4 years ago

3 0

Force that is applied at one point is transmitted to another point using an incompressible fluid.

You might be interested in

Which of the following best explains how algorithms that run on a computer can be used to solve problems?

timama [110]

The statement which best explains how algorithms running on a computer can be used to solve problems is; D. Some problems cannot be solved by an algorithm.

<h3>What is an algorithm?</h3>

An algorithm is simply a standard formula or procedures which is made up of a set of finite steps and instructions that must be executed on a computer, so as to proffer solutions to a problem or solve a problem under appropriate conditions.

However, it should be noted that it is not all problems that can be solved by an algorithm, especially because the required parameters and appropriate conditions are not feasible or met.

Read more on algorithm here: brainly.com/question/24793921

7 0

2 years ago

A researcher develops a new instrument to measure coping skills and conducts a pilot study to compare the new tool with an exist

alexira [117]

Answer:b)convergence.

Explanation: Convergence has the basic meaning as when two or more unit of anything meet to converge or join. In the research , the different types of the tools are brought togather and skills and compare them.The measurement is done through the tools which has the already defined parameters.

Thus this concept is the example of the convergence because the tools are being converged and compared.so, the correct answer is option (B) and other option are incorrect because they have the technique of the contrasting and separation and reading respectively.

3 0

3 years ago

Explain the concept of risk management, including risk identification, assessment, and control.

abruzzese [7]

Answer:

Risk management is the technique that is used for managing the risky situation so that security of the system or organization can be maintained. The risk can be reduced by parameters like monitoring the system,alertness, preventive measures etc. There are terms related with the risk management for prevention of the risk such as risk control ,risk identification and risk assessment .

Risk control is the method that is used for calculating the loss or damage experience and then taking the correct measures to reduce the loss and thus, controlling the risk.
Risk assessment is the analyzation of the threats and source of damage/loss that is caused or can be caused by assessing the whole process and functioning.
Risk identification is the technique through which the threat is listed over a document and sorted in accordance with the category of risk, risk response etc.

7 0

4 years ago

1. Write a class for time objects that store three integer values for hour, minute, and second. Also, write a program to test th

Alla [95]

Answer:

class TIME

{

int hour , min , sec ;

public :

TIME()

{

hour=min=sec=0;

}

TIME( int h , int m , int s )

{

hour = h;

min = m;

sec = s;

}

void change ( int Hour)

{

hour = Hour;

}

void stdtime()

{

if(hour>12)

cout<<"The Standard time is"<<(hour-12)<<":"<<min<<":"<<sec<<"P.M\n";

else

cout<<"The Standard time is"<<hour<<":"<<min<<":"<<sec<<"A.M\n";

}

void miltime()

{

cout<<"The Military time is"<<hour<<":"<<min<<":"<<sec<<" hours\n";

}

};

void main()

{

TIME A , B(13,25,30);

A .stdtime();

A.change(23);

A.miltime();

B.stdtime();

B.change(9);

B.miltime();

}

class elevator

{

int CurrentFloor;

int GoingUp;

int GoingDown;

public:

elevator()

{

CurrentFloor=0;

GoingUp=1;

GoingDown=-1;

}

elevator(int floor)

{

CurrentFloor=floor;

GoingUp=1;

GoingDown=-1;

}

void goUp(int y)

{

if( CurrentFloor>3)

cout<<"\nNO MORE FLOORS\n";

else

CurrentFloor=CurrentFloor+y*GoingUp;

}

void goDown(int x)

{

if(CurrentFloor<0)

cout<<"\nNO MORE FLOORS";

else

CurrentFloor=CurrentFloor+x*GoingDown;

}

};

void main()

{

elevator A(1);

A.goUp(1);

A.goDown(1);

}

6 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago