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shtirl [24]
2 years ago
10

I need help can anyone help me with this pls

Mathematics
1 answer:
Cerrena [4.2K]2 years ago
3 0
It might be 2.5 but I could be wrong
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How do you find answer for 8k=4/9
nasty-shy [4]
Isolate k by dividing both sides by 8

8k=4/9
k=4/72

Reduce if possible

4/72 -> 1/18
8 0
3 years ago
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The graph of f(x) is obtained by translating the graph g(x)=|x| five units down.
lana [24]
F(x)=IxI-5
when you shift it up, add the units to the end of y=IxI
when you shift it down, subtract the units to the end of y=IxI
7 0
2 years ago
Farmer Kipp sold 25 horses for a total of $7500 in January and 25 horses for a total of $10500 in February. What is the average
insens350 [35]

Answer:

So Average Price of horse is $360

Step-by-step explanation:

Given:

25 horses sold in January for $ 2500

25 horses sold in February for $10500

TO find:

Average price of horse = ?

Solution:

Average price is usually found out by adding all the values and dividing by its total no of values

Now in our case

Total Horse = 25 + 25

                     = 50

Total Money = $7500 + $10500

                      = $18000

Average Price =\frac{total price}{total horses}

Average Price =\frac{18000}{50}

                                =$360

So Average Price of horse is $360

3 0
3 years ago
Simplify.055-(0.9-0.8).4
tiny-mole [99]
54.96 Hope this helps
7 0
3 years ago
Read 2 more answers
I NEED HELP!!!
andrey2020 [161]

Answer:

<h2>B. The amount of fuel used was lowest at speeds around 60km/h.</h2>

Step-by-step explanation:

The decreasing part is from (20,13) to (60,6), which gives an average rate of

r=\frac{6-13}{60-20}=-\frac{7}{40}=-0.175

Then, we have an increasing part from (60,6) to (120,10), which gives an average rate of

r=\frac{10-6}{120-60}=\frac{4}{60}=0.067

Basically, at 60 km/h the fuel used was 6 liters per 100 kilometers. Notice that the other velocities make the car to use more liters per kilometers.

Therefore, the amount of fuel used was lowest at speeds around 60 km/h.

6 0
2 years ago
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