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iVinArrow [24]
3 years ago
15

Find the area of the following shape. You must show all work to receive credit A (-4, 0), B(0, 4), C(2, 2), D(1,0)

Mathematics
1 answer:
natulia [17]3 years ago
7 0

9514 1404 393

Answer:

  13 square units

Step-by-step explanation:

See the attached figure.

The horizontal dashed line divides the figure into two pieces:

  • a triangle 4 wide and 2 high
  • a trapezoid 2 high with bases 5 and 4

The appropriate area formulas can be used to find the areas of these. The figure's area will be their sum.

  A = (1/2)bh = (1/2)(4)(2) = 4 . . . . square units

  A = (1/2)(b1 +b2)h = (1/2)(5 +4)(2) = 9 . . . . square units

The area of the shape is ...

  (4 +9) square units = 13 square units

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Need some help please
katovenus [111]

Answer:

the answer is 40.1 cm

Step-by-step explanation:

\cos( \alpha )  = adjacent \div hypotenuse

The adjacent in the triangle is 23cm and the Alpha is 55 degrees, so just insert the formula to find the adjacent which is x .

Tq

8 0
3 years ago
Julio's father is 4 times as old as Julio. The sum of their ages is no less than 55.
seropon [69]
Call (F) the age of the father and (J) the age of Julio

The F & J are related in this way: F=4J

 Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.

Algebraically that is: F + J ≥ 55

You can substitute F with 4J to find the solution for J: 

4J + J ≥ 55

5J ≥ 55

Now divide both sides by 5

5J/5 ≥ 55/5

J ≥ 11 

That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
8 0
3 years ago
How many digits are written when 1000 to the power of 2015 is expressed as a numeral?
PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

1000^{2015}

We have to find the number of digits ,

So,

1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}

Since we know that

10^n\text{ has n+1 number of digits }

so,

10^{6045}\text{ has 6046 number of digits }

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0
3 years ago
What is the derivative of w=(t^2+1)^100<br><br> How is it 200t(t^2+1)^99?
GuDViN [60]
(t^2+1)^100

USE CHAIN RULE

Outside first (using power rule)

100*(t^2+1)^99 * derivative of the inside

100(t^2+1)^99 * d(t^2+1)

100(t^2+1)^99 * 2t

200t(t^2+1)^99
6 0
3 years ago
Read 2 more answers
Y= 9x -9 y= 9 substitution method
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You would plug in the y=9 into the first equation and then have the expression 9=9x-9
. After going through the first steps of solving an expression you would get 18=9x. X=2. Then you would plug in the x value into the first expression to get y=9.
3 0
3 years ago
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