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3 years ago

Put these numbers in order from least to greatest. 8.1 9.81 0.891 0.01

Mathematics

2 answers:

iogann1982 [59]3 years ago

5 0

0.01, 0.891, 8.1, 9.81

11111nata11111 [884]3 years ago

3 0

Answer:

8.1,9.81, 0.891, 0.01

Step-by-step explanation:

YESSIr

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John withdraws $40.00 from her savings account each month. What integer represents the net effect on her balance after 5 months?

lina2011 [118]

Answer:

The net effect of amount in John account after 5 months is $A - $200

Step-by-step explanation:

Given as :

The amount of money withdraws by John each month from his account = $40

Let The total amount of money did John had in his account = $A

Let the amount left in John account after 5 months of withdraw = $x

<u>So, According to question</u>

∵ Each month the money withdraw from account = $40

∴ In 5 months , the money withdraw = $40 × 5

I.e In 5 months , the money withdraw = $200

So, The left money in account after withdraw in 5 months = $A - The amount withdraw in 5 months

I.e x = $A - $200

So, The balance in account after 5 months = x = $A - $200

Hence, The net effect of amount in John account after 5 months is $A - $200 Answer

6 0

3 years ago

A building 50 ft high casts a 75-ft shadow. Sarah casts a 6-ft shadow. The triangle formed by the building and its shadow is sim

Rom4ik [11]

Make each known side into a ratio like so...
75/6
(Because 75 is the shadow casted by the building, and 6 is the shadow casted by sarah)
and 50/x
(50 is how tall the building is and sarah's height is what needs to be found)
Therefore,
75 50
---- -----
6 x

Do cross products;
50 x 6 = 75 x X
300 = 75x
Divide by 75
x = 4ft

8 0

3 years ago

A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c

mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

$P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75$

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

$P(A \cap B) = 0.6*\frac{1}{6} = 0.1$

Find the probability that bridge B was used.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333$

0.1333 = 13.33% probability that bridge B was used.

8 0

3 years ago

Which of the following represents fifth root of x to the fourth power in exponential form? (6 points) a 4x5 b 5x4 c x to the fiv

sleet_krkn [62]

Answer:

B) 5x4

one its not A nor its C

its either B or D but i would go with B because D doesn't make sense all because D is saying x4^5 but its 5x^4

3 0

3 years ago

Read 2 more answers

Andre earns $4,000 a month at his new job in order to track his spending and saving he created a monthly budget. Andre divided h

Alik [6]

Answer:

If Andre plans on staying within his budget, he should choose Apartment 1.

Step-by-step explanation:

Apartment 1: $1100 rent + $250 utilities = $1350 Total Monthly

Apartment 2: $1350 rent + $100 utilities = $1450 Total Monthly

Andre can spend up to $1320 on rent & $320 on utilities, totaling at $1640. In this situation, Andre needs to save as much money as possible. Either on one of these apartments stay below the budget for monthly cost, but Apartment 2's rent goes $30 higher than his budget allows. In the end, this makes apartment 1 the best option for rent, utilities, and ultimate cost.

If Andre plans on staying within his budget, he should choose Apartment 1.

3 0

3 years ago

Put these numbers in order from least to greatest. 8.1 9.81 0.891 0.01​

Put these numbers in order from least to greatest. 8.1 9.81 0.891 0.01