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Neko [114]
3 years ago
8

Multiplying by which number is equivalent to finding 15%?

Mathematics
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

The answer is still 15. Because

  • The number is × which is 0.
  • so it is still 15%
Ahat [919]3 years ago
3 0
.15 is your answer, seeing as .15 is equivalent to 15%
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I need help with this please​
gizmo_the_mogwai [7]
I think the answer is c
3 0
3 years ago
Complete the table below.
ziro4ka [17]

Here's what I got.

Column C, starting from the top and going down: $12.33, $13.00, $10.50, $10.00, $6.00, $8.00, $4.25, $10.50, $11.50, and $8.50

Column F, Starting from the top and going down: $4,650, $4,650, $4,650, $4,600, $4,600, $4,600, $5,000, $5,000, $4,625, and $4,625.

I don't really understand column G yet, so that's all I have. Hope it helped a little bit.

7 0
3 years ago
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Find the surface area of a square pyramid with base edges<br> of 5 cm and a slant height of 3 cm.
ch4aika [34]

Answer:

Surface area of square pyramid = 55cm^{2}

Step-by-step explanation:

Let, b is the base  edges and s is the slant height

According to given condition:

b = 5 cm

s = 3 cm

Find out:

Surface area of square pyramid = ?

Formula:

Surface area of square pyramid = b^{2} + 2bs

Solution:

Surface area of square pyramid = b^{2} + 2bs

Surface area of square pyramid = 5^{2} + 2(5)(3)

Surface area of square pyramid = (25+ 30 ) cm^{2}

Surface area of square pyramid = 55cm^{2}

3 0
4 years ago
Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput
Andrej [43]

Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

P = C_{n,x}.p^{n}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so p = 0.53

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 0 successes, so x = 0.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{0}.(0.47)^{4}

P = 0.0488

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 4.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{4}.(0.47)^{0}

P = 0.0789

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 2.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,2}.(0.53)^{2}.(0.47)^{2}

P = 0.3723

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0
3 years ago
Please help!... its due tonight and i need help
myrzilka [38]
It’s the last one (10,800)
3 0
3 years ago
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