The solution for this problem:
The distance in mega parsec is equal to recession velocity / H, where h is equal to 50 mega parsec.The explanation for this is:1 parsec = 2.E+05 AU, nearly. 50 mega parsec = 1. E+13 AU, nearly. 1 mega means E+06 (million).
Answer:
Explanation:
B- The red horse's average speed was greater than the black horse's average speed.
Red average speed = 1/120 = 0.00833 mi/s
Black average speed = 1/150 = 0.00667 mi/s
we only know about average speed based on the information given. Either horse could have had higher or lower, even negative, instantaneous speed during some phase of the race.
Did you ever figure it out, bc now I need it lol.
The tension in each of the ropes is 625 N.
Draw a free body diagram for the bag of food as shown in the attached diagram. Since the bag hangs from the midpoint of the rope, the rope makes equal angles θ with the horizontal. The tensions <em>T</em> in both the ropes are also equal.
Resolve the tension T in the ropes into horizontal and vertical components T cosθ and T sinθ respectively, as shown in the figure. At equilibrium,
......(1)
Calculate the value of sinθ using the right angled triangles from the diagram.
Substitute the value of sinθ in equation (1) and simplify to obtain T.
Thus the tension in the rope is 625 N.
It's not so much a "contradiction" as an approximation. Newton's law of gravitation is an inverse square law whose range is large. It keeps people on the ground, and it keeps satellites in orbit and that's some thousands of km. The force on someone on the ground - their weight - is probably a lot larger than the centripetal force keeping a satellite in orbit (though I've not actually done a calculation to totally verify this). The distance a falling body - a coin, say - travels is very small, and over such a small distance gravity is assumed/approximated to be constant.
