Answer:
<h2>0.9 Joules</h2>
Explanation:
Elastic potential energy of a spring= 1/2 × Spring constant × displacement²
following calculations you will get ur answer!!
Answer : 63 km/h
Explanation :
Outgoing distance = 300 km.
Outgoing speed = 93 km/h.
Break time = 1 h
Return distance = 300 km
Return speed = 56 km/h
Outgoing time = outgoing distance / outgoing speed
Outgoing time = 300 km / 93 km/h = 3.225806451612 h
Return time = return distance / return speed
Return time = 300 km / 56 km/h = 5.357142867142 h
Total distance =. Outgoing distance + return distance travelled
Total distance = 300 km + 300 km = 600 km
Total time = outgoing time + break time + return time
Total time = 3.225806451612 h + 1 h+ 5. 357142867142 h = 9.582949308754 h
Average speed = total distance / total time
Average speed = 600 km / 9.582949308754 h
Average speed = 62.61120462042 km/h = 63 km/h
Nearly 14 billion years, according to astronomers. Happy to help!
Answer:
v = 306.76 Km/h
Explanation:
given,
height of the aircraft = 3000 m
differential pressure reading = 3300 N/m²
density of air = 0.909 Kg/m³
speed of aircraft = ?
Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.
using Bernoulli's equation

where ρ is the density of the air at 3000 m



v = 85.21 m/s

v = 306.76 Km/h
So,
The conversion factor is:

So, if we plug in the numbers, we get:

Multiply

Add 32

5500 degrees Celsius = 9932 degrees Farenheit.