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s2008m [1.1K]
3 years ago
7

A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse

Physics
2 answers:
Lyrx [107]3 years ago
5 0

Answer:

Explanation:

B- The red horse's average speed was greater than the black horse's average speed.

Red average speed = 1/120 = 0.00833 mi/s

Black average speed = 1/150 = 0.00667 mi/s

we only know about average speed based on the information given. Either horse could have had higher or lower, even negative,  instantaneous speed during some phase of the race.

GalinKa [24]3 years ago
4 0

Answer

your format is incorrect!!

Explanation:

there is no such thing as a red horse. there are chestnuts, bays and red roans, just no reds. usually though, blacks are faster scientifically than red roans.

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<span>They are killed mostly by heart attacks. Alternating electrical current interferes with the electrical pulses of the heart produced by the Sino-atrial node hence cause the heart to beat erratically and hence a heart attack and death to result. 7 milliamps to your heart for 3 seconds can cause it to be arrhythmic. </span>




8 0
4 years ago
Determine the magnitude of the resultant force acting on a 5 −kg particle at the instant t=2 s, if the particle is moving along
Alex787 [66]

Answer:

F = 296.7N

Explanation:

The x and y component of the position vector are given by:

x(t) =rcos\phi, y(t) = rsin\phi\\ \frac{dx}{dt} =\frac{dr}{dt} cos\phi - rsin\phi\frac{d\phi}{dt} , \frac{dy}{dt}=\frac{dr}{dt}sin\phi + rcos\phi\frac{d\phi}{dt}\\ \frac{d^2x}{dt^2} = \frac{d^2r}{dt^2} cos\phi - \frac{dr}{dt} sin\phi\frac{d\phi}{dt} -\frac{dr}{dt} sin\phi\frac{d\phi}{dt} - r(cos\phi\frac{d^2\phi}{dt^2} + sin\phi\frac{d^2\phi}{dt^2})

\frac{d^2y}{dt^2} = \frac{d^2r}{dt^2} sin\phi + \frac{dr}{dt} cos\phi\frac{d\phi}{dt}+\frac{dr}{dt}cos\phi\frac{d\phi}{dt}+r(-sin\phi\frac{d^2\phi}{dt^2} +cos\phi\frac{d^2\phi}{dt^2})

At t = 2s:

\phi(2) = 1.5t^2-6t= -6\\ \frac{d\phi}{dt}(2) = 3t-6=0\\ \frac{d^2\phi}{dt^2}=3\\r(2)=2t+10=14\\ \frac{dr}{dt}=2\\\frac{d^2r}{dt^2} = 0

Plugging in:

\frac{d^2x}{dt^2}=-42(cos(-6) + sin(-6))=-52\frac{m}{s^2} \\\frac{d^2y}{dt^2} = 42(cos(-6)-sin(-6))=28.6\frac{m}{s^2}

The resulting force F is:

F = m\sqrt{(\frac{d^2x}{dt^2})^2 + (\frac{d^2y}{dt^2})^2}=296.7N

5 0
3 years ago
Which of the following maxims would apply to a person with a Type A personality?
lozanna [386]

The correct answer is C. Lost time is never found again

Explanation:

One of the most relevant personality theories is Type A and Type B personality theory that proposes two main types of personalities by grouping different personality traits. In the case of Type A personality, this refers to individuals that are very organized, impatient, and concerned with time and goals. On the opposite, Type B personality includes individuals that are more relaxed in different aspects.

According to this, one maxim that applies to Type A personality is "Lost time is never found again" because people with this personality are concerned about time and therefore, loss of time is considered highly negative by them. Also, due to their ambitions and concern with goals they want to avoid losing time as this is equivalent to work, money, goals, etc.

4 0
3 years ago
A burner is placed below the right side of the beaker. Which image shows the motionvof of the liquid that will result? it's a gi
Kipish [7]

Answer:

the second picture

Explanation:

4 0
3 years ago
__________ is the ability to model the components of a system, to connect the inputs and outputs among those components into a s
nirvana33 [79]

Answer:

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Explanation:

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It is therefore, the ability for the modelling of the system's component, to make the components connection to the input/output in order to reflect the dynamics and built-up of a system.

8 0
3 years ago
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