Answer:
The induced current and the power dissipated through the resistor are 0.5 mA and 
.
Explanation:
Given that,
Distance = 1.0 m
Resistance = 3.0 Ω
Speed = 35 m/s
Angle = 53°
Magnetic field 
(a). We need to calculate the induced emf
Using formula of emf
Where, B = magnetic field
l = length
v = velocity
Put the value into the formula
We need to calculate the induced current
Put the value into the formula
(b). We need to calculate the power dissipated through the resistor
Using formula of power
Put the value into the formula
Hence, The induced current and the power dissipated through the resistor are 0.5 mA and .
It takes sunlight 8 minutes to reach earth , so yes
It is eight times more than the star A.
<h3>What is luminosity and on which it depends?</h3>
The luminosity of an object is a measure of its intrinsic brightness and is defined as the amount of energy the object emits in a fixed time.
luminousity depends upon the two factors are:
1) The star's actual brightness
Some stars are naturally more luminous than others ,so the brightness level from one star to next star is significantly different.
2) The star distance from us
The more distance of an object the dimmer it appears.
Energy emitted = sAT⁴
where s is stefan constant
A is surface area and T is temperature .
to learn more about Luminosity click here brainly.com/question/14140223
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Answer: The electric field is: a) r<a , E0=; b) a<r<b E=ρ (r-a)/εo;
c) r>b E=ρ b (b-a)/r*εo
Explanation: In order to solve this problem we have to use the Gaussian law in diffrengios regions.
As we know,
∫E.dr= Qinside/εo
For r<a --->Qinside=0 then E=0
for a<r<b er have
E*2π*r*L= Q inside/εo in this case Qinside= ρ.Vol=ρ*2*π*r*(r-a)*L
E*2π*r*L =ρ*2*π*r* (r-a)*L/εo
E=ρ*(r-a)/εo
Finally for r>b
E*2π*r*L =ρ*2*π*b* (b-a)*L/εo
E=ρ*b* (b-a)*/r*εo
