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Schach [20]
3 years ago
14

Can someone help me !

Mathematics
2 answers:
Xelga [282]3 years ago
6 0

Answer:

its b

Step-by-step explanation:

hope this helps

zloy xaker [14]3 years ago
4 0
It’s alternate extior angles the answer is b.. hope this is helpful!
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A recipe that makes 8 jumbo blueberry muffins calls for 1 1/2 teaspoons of baking powder how much making baking powder is needed
nirvana33 [79]

we know that

For make 8 jumbo blueberry muffins is needed 1\frac{1}{2} teaspoons of baking powder

1\frac{1}{2}=1.5

So

by proportion

\frac{8}{1.5} =\frac{36}{x} \\ \\ 8x=36*1.5\\ \\ x=\frac{36*1.5}{8} \\ \\ x=6.75

x=6\frac{3}{4} teaspoons of baking powder

therefore

the answer is

6\frac{3}{4} teaspoons of baking powder

7 0
4 years ago
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You are watching a commercial on television for the newest sandwich at ur favorite fast food chain.what type of promotion are u
zheka24 [161]
You are watching an advertisement 

4 0
3 years ago
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What is the solution to the inequality? m/-2 <10
Anna11 [10]

Answer:

m>-20

Step-by-step explanation:

to leave m alone you need to multiply -2 to the other side but when you do that the sign changes because its by a negative.

7 0
3 years ago
A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not
castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

<h3><u>Find P(B)</u></h3>

P(B) = \frac{8}{12}

<h3><u>Find P(B n R)</u></h3>

P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}

<h3><u>Find </u><u> P(R | B)</u></h3><h3>P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}</h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

4 0
4 years ago
Which event includes an example of a dependent event? A) A coin is flipped. The result is recorded. The coin is then flipped a s
tiny-mole [99]
I am pretty sure it is D.
All the other ones don't affect the second activity...
Hope I helped...
6 0
3 years ago
Read 2 more answers
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