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3 years ago

Can someone help me !

Mathematics

2 answers:

Xelga [282]3 years ago

6 0

Answer:

its b

Step-by-step explanation:

hope this helps

zloy xaker [14]3 years ago

4 0

It’s alternate extior angles the answer is b.. hope this is helpful!

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The volume of the box is modeled by the function V (x) = 5x^2 + 5x. What is the volume when x= 4?

liubo4ka [24]

V= 5 x 4^2 + 5 x 4
V= 5 x 16 + 20
V= 80+ 20
V= 100
Answer is C 100 cubic units

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3 years ago

Write an equation of the line that passes through each point with the given slope, (3,5) and m=2.

icang [17]

Answer:

The point slope formula states (y-y1)=m(x-x1)

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Substituting the point and slope from the problem give

(y-5)=-2(x-3) ~answer

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3 years ago

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Answer:

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3 classmates share 2 granola bars equally.

umka21 [38]

Answer:

3/2 or 1.5

Step-by-step explanation:

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5 0

3 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago