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GalinKa [24]
3 years ago
12

What should be the first step to solve the equation? 2x + 9(x – 1) = 8(2x + 2) – 5

Mathematics
1 answer:
alexira [117]3 years ago
5 0

Answer: The first step to solving this equation would be to use the distributive property to execute the parentheses.

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How are fractions related to decimals
irina1246 [14]
Fractions and decimals can be written as a percent
6 0
3 years ago
Read 2 more answers
What are the domain and range of the function? The domain is the set of integers, and the range is y > 4. The domain is the s
Andreas93 [3]

Answer:

the answer is D

Step-by-step explanation:

on edge2020

3 0
3 years ago
Read 2 more answers
I need help finding this answer please
Maslowich
To solve this you need to use the formula for Chord-Chord length. You need to know it, it is ab=cd. with this, we can plug numbers in.
a=30
b=x+1
c=2x-6
d=21
So our new equation is:
30(x+1)=21(2x-6)
30x+30=42x-126
156=12x
x=13
This isn't what the question is askign for though, it wants YZ
Which is A+B or 30+x+1 or 21+13=34. 
YZ=34

8 0
3 years ago
in a final exam you have four multliple choice questions left to do. each questions has five suggested answers and only one of t
kompoz [17]

Answer:

The probability that you get zero questions correct is 0.4096

The probability that you get one questions correct is 0.4096

The probability that you get three questions correct is 0.0256

Step-by-step explanation:

These probability can be describe with a Binomial Distribution. These distribution can be used when we have n identical and independent situations in which there is a probability p or probability of success and a probability q or probability of fail. Additionally q is equal to 1 - p. The probability of x for a situation in which we can apply binomial distribution is:

P( x,n,p) = n Cx * p^{x } * q^ {n-x}

Where x is the variable that says the number of success in the n situations

And nCx is calculate as:

nC x = \frac{ n!}{ x! (n-x)! }

From the question we can identify that:

  • n is equal to 4 multiple choice question
  • p is 1/5 or 0.2, the probability of get one question correct
  • q is 4/5 or 0.8, the probability of get one question incorrect

Then the probability of get zero questions correct of 4 questions is:

P( 0, 4, 0.2) = 4 C0 * p^{0 } * q^ {4-0}= 0.4096

The probability of get one question correct of 4 questions is:

P( 1, 4, 0.2) = 4 C1 * p^{1 } * q^ {4-1}= 0.4096

The probability of get three questions correct of 4 questions is:

P( 3, 4, 0.2) = 4 C3 * p^{3 } * q^ {4-3}= 0.0256

8 0
4 years ago
M is the midpoint of EF, EM = 3x – 2, and MF = x + 8.<br><br> What is MF?<br><br> MF =
murzikaleks [220]
4x + 6
3x - 2 = x + 8
x = 5
MF = 26
6 0
3 years ago
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