Answer:
-2a-4n+14
Step-by-step explanation:
Answer:
The probability there will be between 280 and 360 column inches of classified advertisement
P(280≤X≤360) = P(-2≤Z≤2) = 0.9544
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean the population = 320
The standard deviation of the Population = 20
Let 'X' be the random variable in a normal distribution
Let 'X' = 280

Let 'X' = 360

<u><em>Step(iii):-</em></u>
The probability there will be between 280 and 360 column inches of classified advertisement
P(280≤X≤360) = P(-2≤Z≤2)
= P(z≤2) -P(z≤-2)
= P(z≤2)+P(z≤2)
= 2P(z≤2)
= 2×0.4772 ( from normal table)
= 0.9544
Sixty-nine thousand, a hundred and eight?
Area of the squares (6):
A 1 = 6 · 10² = 600 in²
Area of the equilateral triangles (6):
A 2 = 6 · 10²√3 / 4 = = 6 · 25 · 1.73 = 259.8 in²
Area of the hexagon:
A 3 = 6 · 10²√3/4 = 259.8 in²
Total area:
600 + 259.8 + 259.8 = 1,119.6 in²
Answer: C )