So we gots apolynomial equation that is 3rd degree and crosses x axis at x=-1, x=0 and x=2
the factors of a poly equation that passes through r1,r2,r3 is
(x-r1)(x-r2)(x-r3)
so
r1=-1
r2=0
r3=2
f(x)=(x-(-1))(x-0)(x-2)
f(x)=(x+1)(x)(x-2)
f(x)=x³-x²-2x
leading coefient is posiitve because 3rd degree equations that are postive go bottom left to top right
yah
actually that looks like the exact graph
both
f(x)=(x+1)(x)(x-2)
and
f(x)=x³-x²-2x
are correct
Since CB || ED and CB = ED,
by the alternate interior angles theorem,
mE = mC, and mD = mB.
with CB = ED, we can conclude that CBF = EDF, by SAS congruent theorem.
It would be 120.
Look at the first column, 40. It’s basically multiplication and you can just use a calculator.
For example, 40 x 1 = 40,
And if you looks the second column, it’s being multiplied by 2. Which would be 40 x 2, you just have to multiply 3 x 40 which is 120.
Sorry for my english
Step-by-step explanation:
We observe the line graph.
For every 1 block across, the line goes up by 2 blocks. Therefore Slope = Rise/Run = (2)/(1) = 2.
Also, the y-intercept when x = 0 is 2.
Slope-intercept form: y = mx + c
Hence we have y = 2x + 2. (C)
