Answer:
d) The limit does not exist
General Formulas and Concepts:
<u>Calculus</u>
Limits
- Right-Side Limit:

- Left-Side Limit:

Limit Rule [Variable Direct Substitution]: 
Limit Property [Addition/Subtraction]: ![\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bx%20%5Cto%20c%7D%20%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%20%3D%20%20%5Clim_%7Bx%20%5Cto%20c%7D%20f%28x%29%20%5Cpm%20%5Clim_%7Bx%20%5Cto%20c%7D%20g%28x%29)
Step-by-step explanation:
*Note:
In order for a limit to exist, the right-side and left-side limits must equal each other.
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Find Right-Side Limit</u>
- Substitute in function [Limit]:

- Evaluate limit [Limit Rule - Variable Direct Substitution]:

<u>Step 3: Find Left-Side Limit</u>
- Substitute in function [Limit]:

- Evaluate limit [Limit Rule - Variable Direct Substitution]:

∴ Since
, then 
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
The equation of the line which is plotted on the graph and passes from the points (2,5) and (-2,-3) is y=2x-6.
<h3>What is the equation of line?</h3>
The equation of the line is the way of representation of a line in the equation form.
The equitation of the lines represents the line by the set of points on which the line lies or passes through in the coordinate system.
The formula to find equation of line is,
(y-y₁)={(y₂-y₁)/(x₂-x₁)}(x-x₁)
Here, x and y are the coordinate and subscript (1,2) used for the first and second point.
The points from which the line passes through are (2,5) and (-2,-3). Put the values,
(y-y₁)={(y₂-y₁)/(x₂-x₁)}(x-x₁)
(y-(-2))={(-3-5)/(-2-2)}(x-2)
y+2={-8/-4}(x-2)
y+2=2(x-2)
y+2=2x-4
y=2x-4-2
y=2x-6
Thus, the equation of the line which is plotted on the graph and passes from the points (2,5) and (-2,-3) is y=2x-6.
Learn more about the equation of line here;
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the answer to this is
Angle ABE= 56
Angle CBD= 56
Angle ABC= 124
Answer:
y = x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 1, thus
y = x + c ← is the partial equation
To find c substitute (5, 3) into the partial equation
3 = 5 + c ⇒ c = 3 - 5 = - 2
y = x - 2 ← equation of line
The probability that exactly one of the three candies is defective is 1/3