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ad-work [718]
3 years ago
13

(-3y^2 — 5у — 2) +(-7y^2- 5y + 2)

Mathematics
2 answers:
levacccp [35]3 years ago
5 0

Answer:

-10y^2-10y

Step-by-step explanation:

Combine like-terms: -10y^2-10y

Snowcat [4.5K]3 years ago
5 0

\text{Combine like terms:}\\\\(-3y^2 - 5y- 2) +(-7y^2- 5y + 2)\\\\-3y^2 - 5y- 2 -7y^2- 5y + 2\\\\-10y^2-5y-5y-2+2\\\\-10y^2-10y-2+2\\\\\boxed{-10y^2-10y}

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2 years ago
The sum of squares of two
Elanso [62]

Answer:

the product of the 2 numbers is 22

Step-by-step explanation:

x² + y² = 80

(x - y)² = 36

=>

x - y = 6

or y - x = 6

let's start with the first one x-y=6

x = 6 + y

=>

(6+y)² + y² = 80

y² + 6y +6y + 36 + y² = 80

2y² + 12y + 36 = 80

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y² + 6y - 22 = 0

the solution of a quadratic equation

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case here we have an squadron in y.

a=1

b=6

c=-22

(-6 ± sqrt(36 + 4×22))/2 = (-6 ± sqrt(36+88))/2 =

= (-6 ± sqrt(124))/2 = (-6 ± sqrt(4×31))/2 =

= (-6 ± 2×sqrt(31))/2 = -3 ± sqrt(31)

y1 = -3 + sqrt(31)

y2 = -3 - sqrt(31)

=>

x1 = 6 + -3 + sqrt(31) = 3 + sqrt(31)

x2 = 3 - sqrt(31)

control :

(-3 + sqrt(31))² + (3 + sqrt(31))² = 80

9 - 3 sqrt(31) - 3 sqrt(31) + 31 + 9 +3 sqrt(31) + 3 sqrt(31) + 31 = 80

9 + 31 + 9 +31 = 80

18 + 62 = 80

80 = 80 correct

solving now for y-x=6

delivers exactly the same calculations, just with x and y trading places.

so, the resulting 2 number pairs are the same.

the product of the 2 numbers :

(3 + sqrt(31))(-3 + sqrt(31)) = -9 - 3 sqrt(31) + 3 sqrt(31) + 31 =

= -9 + 31 = 22

(3 - sqrt(31))(-3 - sqrt(31)) = -9 + 3 sqrt(31) - 3 sqrt(31) + 31 =

= 22

so, the product is the same in both cases.

6 0
2 years ago
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MaRussiya [10]
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