Given the equation 2y = 5x - 3:
A way to find out which of the ordered pair options lie on the line is to substitute their coordinates into the equation.
A) (2, 5)
2y = 5x - 3
2(5) = 5(2) - 3
10 = 10 - 3
10 = 7 (False statement). this means that (2, 5) is not a solution to the given equation.
B) (6, 3)
2y = 5x - 3
2(3) = 5(6) - 3
6 = 30 - 3
6 = 27 (False statement). this means that (6, 3) is not a solution to the given equation.
C) (3, -6)
2y = 5x - 3
2(-6) = 5(3) - 3
-12 = 15 - 3
-12 = 12 (False statement). this means that (3, -6) is not a solution to the given equation.
D) (3, 6)
2y = 5x - 3
2(6) = 5(3) -3
12 = 15 - 3
12 = 12 (True statement). This means that (3, 6) IS a solution to the given equation.
E) (2, -5)
2y = 5x - 3
2(-5) = 5(2) - 3
-10 = 10 - 3
-10 = 7 (False statement). this means that (2, -5) is not a solution to the given equation.
Therefore, the correct answer is Option D: (3, 6).
Answer:
X <= 4
Step-by-step explanation:
-3x - 24<= -36
Make -3x the subject, by carrying -24 to the other side
Note: Moving -24 to the other side changes to + 24
-3x <= -36 + 24
-3x <= - 12
Minus cancels minus
3x <= 12
Divide both sides by 3,to get the value of x
3x/3 <= 12/3
x <= 12/3
x <= 4
Therefore, x equals to 4
Ok
first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0
then simplify
any factors you factored out is now a hole, remember them
to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve
so
y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0
no factors to simplify so no holes
set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1
x+1=0
x=-1
the horizontal assemtotes are x=1 and -1
Answer:
Step-by-step explanation:
Answer:
r = 8
Step-by-step explanation:
6r = 95-47
6r = 48
r = 48/6
r = 8
