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3 years ago

A school had a girl:boy ratio 5.4.

Mathematics

1 answer:

Ilya [14]3 years ago

8 0

Answer:

164

The 982 part seems wrong. Are you sure it isn't 981?

around 436 if I use 981 instead. 982 would give a decimal and that would be kinda weird for a part human.

Step-by-step explanation:

You can divide the 205 by 5 to simplify the ratio down. 205/5 = 41. Then you can multiply by 4 to find then number of boys.

981

So you can add the 5 and 4 together to 9 and then divide 981 by 9 to get 109. Then you can multiply by 4 to get 436.

Hope this helps!

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A saving account earns 4.5 simple interest per year. If 650.00 is deposited and no withdrawals or deposits are made during one y

kramer

Answer:

29.25 Interest

Step-by-step explanation:

Take the formula: I=PRT

The principal is 650.00, 4.5 is the rate, 1 year is the time, We do not know the interest.

Change the rate, 4.5 to 0.045 to help solve the problem.

Times 650.00, 0.045, and 1 together.

You will get 29.25, Which is the answer!

Booyah! You are done.

Hope this helps!

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3 years ago

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pickupchik [31]

Answer:

B. M Y, G T, B W, segment MG segment YT, segment GB segment TW, segment MB segment YW

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The graph shows how many apples Erin can pick if she maintains a constant rate. What is the linear equation for this relationshi

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Which pair of variables can possibly be correlated (as opposed to associated)?

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3 years ago

Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2

ankoles [38]

Option C:

$2 g^{3}-5 g^{2}+6$

Solution:

Given expression:

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

To find which expression is equal to the given expression.

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

Expand the term $-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12$

$$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}$

Arrange the like terms together.

$$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}$

$$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}$

Factor the numerator $2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)$

$$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}$

Cancel the common factor g + 2, we get

$=2 g^{3}-5 g^{2}+6$

Hence option C is the correct answer.

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3 years ago

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