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solong [7]
3 years ago
8

Solve x2 + 62 – 1 = 0 by completing the square.

Physics
1 answer:
Ymorist [56]3 years ago
4 0
X=-61/2 and how to solve it step by step it is in the photo

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How much net force is required to accelerate a 0.5 kg toy car, initially at rest to a velocity of 2.4 m/s in 6s?
Jet001 [13]
Force = 0.20N .F = m ×a .& a = v/t then the f = m×v/t

3 0
4 years ago
A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
Bad White [126]

Answer:

N=1.64\times10^{19}

R=19.54\Omega

V=10.28V

Explanation:

By definition I=Q/t, so we can calculate the total charge that went through the filament since we know the electric current and the time. If the charge of one electron is e, then the total charge will be given by Q=Ne. Combining these equations we get the number of electrons as:

N=\frac{Q}{e}=\frac{It}{e}=\frac{(0.526A)(5s)}{1.602\times10^{-19}C}=1.64\times10^{19}

Since the resistivity of tungsten (W) is \rho_W=5.6
\times10^{-8}\Omega m, then resistance can be calculated using the formula:

R=\rho_W\frac{L}{A}=\rho_W\frac{L}{\pi r^2}=(5.6\times10^{-8}\Omega m)\frac{(0.58m)}{\pi (0.000023m)^2}=19.54\Omega

Where we already obtained the radius from the diameter. Finally the Voltage will be given by the formula:

V=RI=(19.54\Omega)(0.526A)=10.28V

3 0
3 years ago
Equals distance divided by time.<br> speed<br> distance<br> time<br> O acceleration
zloy xaker [14]

Answer:

<h2>speed</h2>

Explanation:

<u>Rule</u><u>:</u>

<h3>Speed= Distance/ Time</h3>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em>

7 0
3 years ago
A concave lens has a focal length of 25cm. it's power in diaptor is​
IgorLugansk [536]

As we know that :

\begin{gathered}\large{\boxed{\sf{P \: = \: \dfrac{1}{f}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{1}{-25}}}\end{gathered}

Power, is in Meter. So divide focal length by 100

\begin{gathered}\rightarrow {\sf{P \: = \: \dfrac{1}{\dfrac{-25}{100}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{-100}{25}}} \\ \\ \rightarrow {\sf{P \: = \:- 4}} \\ \\ \underline{\sf{\therefore \: Power \: of \: Concave \: lens \: is \: - \: 4D}}\end{gathered}

8 0
2 years ago
Which of the following could be used as biomass fuel? Check all that apply. A. Rocks B. Corn stalks C. Plastic D. A tree
allsm [11]
Biomass fuel is produced from organic materials. Therefore, B and D apply. This fuel can be created from fertilizer, crops, lumber, etc. 
4 0
4 years ago
Read 2 more answers
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