Does it have to be that exact word. cause it is just another term for psuedopodium
I agree the best choice is A............
Answer:
1440 W
Explanation:
First of all, we can find the total displacement of the sled, which is given by

where
a = 0.08 m/s^2 is the acceleration
t = 1 min = 60 s is the time
Substituting,

Now we can find the wotk done on the sled, equal to the product between force and displacement:

And finally we can fidn the average power, which is the ratio between the work done and the time taken:

Answer:
= 3.87 m/s
Explanation:
Since momentum is conserved, momentum right before and after the boy jumps onto the skateboard should be the same.
Initial momentum = momentum of boy = 43.2 x 4.10 = 177 kg·m/s
Final momentum = momentum of boy and skateboard = (43.2 + 2.50) x v = 45.7v
177 = 45.7v
v = 177 / 45.7 = 3.87 m/s
(Hope this helps can I pls have brainlist (crown)☺️)