Answer:
Distance from the moon= dm= 384,403km
A quarter diameter= dq= 2.3 cm= 0.000023km
No of quarters= 16,713,173, 913
To convert cm into km divide cm by 100 and then by 1000
as
1m= 100cm
1km= 1000m
Therefore
2.3/100= 0.023 m
And
0.023/1000= 0.000023 km
Dividing the distance from the moon by the diameter of the quarter laid end to end would give the number of the quarters needed.
No. of quarters= Distance from the moon/ Diameter of the quarter
= 384,403km/0.000023 km
= 16,713,173,913.043
Rounding 16,713,173,913.043 gives 16,713,173,913 quarters
Explanation:
Brainliest, please!
Answer:
<em>Stellar evolution is the process by which a star changes over the course of time. Depending on the mass of the star, its lifetime can range from a few million years for the most massive to trillions of years for the least massive, which is considerably longer than the age of the universe. The table shows the lifetimes of stars as a function of their masses.[1] All stars are formed from collapsing clouds of gas and dust, often called nebulae or molecular clouds. Over the course of millions of years, these protostars settle down into a state of equilibrium, becoming what is known as a main-seque</em>
Answer:
C. The wheel with spokes has about twice the KE.
Explanation:
Given that
Mass , radius and the angular speed for both the wheels are same.
radius = r
Mass = m
Angular speed = ω
The angular kinetic energy KE given as

I=Moment of inertia for wheels
Wheel made of spokes
I₁ = m r²
Wheel like a disk
I₂ = 0.5 m r²
Now by comparing kinetic energy



KE₁= 2 KE₂
Therefore answer is C.
Answer:
0.03 A
Explanation:
From the question given above, the following data were obtained:
Voltage (V) = 12 V
Resistor (R) = 470 Ω
Current (I) =?
From ohm's law, the voltage, current and resistor are related by the following formula:
Voltage = current × resistor
V = IR
With the above formula, we can obtain the current in the circuit as follow:
Voltage (V) = 12 V
Resistor (R) = 470 Ω
Current (I) =?
V = IR
12 = I × 470
Divide both side by 470
I = 12 / 470
I = 0.03 A
Thus, the current in the circuit is 0.03 A