Answer:
58.56 J
Explanation:
Since the formula for gravitational potential energy is:
GE = m x g x h - where m = mass (kg), g = acceleration due to gravity (9.81 m/s²), h = height (m)
GE= 3 x 9.81 x 2
GE = 58.86 J
Hope this helps
Taking the vertical component of the displacement
1.1 - 0.2 = 0.9 mile
The horizontal component of the displacement
-0.3 mile
The magnitude of the displacement is
√[ (0.9)² + (-0.3) ] = 0.95 mile
The direction is
θ = tan-1 (-0.3/0.9)
θ = 161.57 degrees.
B they start moving around and stop staying in an orderly manner
Answer:
W = 181.26 J
Explanation:
Given that,
The force acting on the cart, F = 20 N
It is at an angle of 25 degrees above the horizontal to move a crate a distance of 10m across the floor.
We need to find work done by the student. The work done by the student is given by :
So, the required work done is 181.26 J.
Answer:
9.0 m
Explanation:
Applying
V = kq/r......................... Equation 1
Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.
make r the subject of the equation
r = kq/V................... Equation 2
From the question,
Given: q = 1.00×10⁻⁵ C, V = 10000 V
Constant: k = 9.0×10⁹ N⋅m²/C²
Substitute these values into equation 2
r = (9.0×10⁹×1.00×10⁻⁵)/10000
r = 9.0 m