Answer:
let the numbers be, x and x+1 ( as it is consecutive number the next number will have 1 more than the number )
sum = 41
so, x + ( x + 1 ) = 41
x + x + 1 = 41
2x + 1 = 41
2x = 41 -1 = 40
2x = 40
x = 40/2 = 20
x = 20
x + 1 = 20 + 1 = 21
so the consecutive numbers whose sum is 40 are, 20 and 21
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Answer:
e = -1/2
Step-by-step explanation:
4/3 = -6e - 5/3
transfer -6e to the right
4/3 = -5/3 -6e
Find the LCM of 3,3and 1
and their LCM is 3. So, divide all through by 3
3(4/3) = 3(-5/3) - 6e × 3
4 = -5 -18e
combine
4 + 5 = -18e
9 = -18e
divide by -18
9/ -18 = -18e/ -18
-1/2 = e
e = -1/2
