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just olya [345]
2 years ago
10

A circle has a diameter

Mathematics
1 answer:
Blizzard [7]2 years ago
7 0

6pi/75

pls mark me as brainlist

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What will be the average of the first five<br> consecutive numbers starting from 11
S_A_V [24]

Answer:

  13

Step-by-step explanation:

The average of any 5 consecutive numbers is the 3rd one (the middle one of the group). The third consecutive number starting from 11 is 13.

The average of {11, 12, 13, 14, 15} is 13.

4 0
2 years ago
1. Write an exponential function to represent the spread of Ben's social media post.
Zina [86]

Answer:

What does ur question mean how to answer it on notebook or pic

8 0
2 years ago
Given an array A = [a1, a2, . . . , an] of nonnegative integers, consider the following problems: 1 P Partition: Determine wheth
boyakko [2]

Answer:

i think the answer is a

Step-by-step explanation:

5 0
3 years ago
Please answer this !
AURORKA [14]

Answer:

50

Step-by-step explanation:

Using the experimental probability, first we have to find total amount paint then to find the amount of good quality forever paint we have to subtract the amounts of other paints from total amount.

Let x represents the amount of good quality forever paint sold.

Total amount of paint =48+45+35+39+33+x=200+x     ...(i)

Experimental probability of paint sold will be better quality durable paint is

P=\dfrac{\text{Amount of better quality durable paint}}{\text{Amount of total paint}}

P=\dfrac{45}{\text{Amount of total paint}}

It is given that experimental probability of paint sold will be better quality durable paint is \frac{9}{50}.

\frac{9}{50}=\dfrac{45}{\text{Amount of total paint}}

\text{Amount of total paint}=\dfrac{45\times 50}{9}

\text{Amount of total paint}=250     ...(ii)

From (i) and (ii), we get

200+x=250

x=250-200

x=50

Therefore, 50 gallons good quality forever paint is sold.

8 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
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