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bixtya [17]
3 years ago
13

please, i need help like now!! Does anyone know what the mean absolute deviation means and how to solve it. i already searched i

t and it was no help.
Mathematics
1 answer:
Alona [7]3 years ago
8 0
<span> the mean absolute deviation is the average absolute deviation from the mean and is a common measure of forecast error in time series analysis. </span>
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3 (x + 1) - 5 = 3x - 2<br> has how many solutions?
marissa [1.9K]

Answer:

Zero Solutions

Step-by-step explanation:

3x+3-5=3x-2

3x-3x= -2+5

0= 3

0 does not equal 3, so zero solutions.

7 0
2 years ago
Which of<br> the following describes the polynomial function?
expeople1 [14]

Answer:

can you put an illustration or picture for me to understand what your saying?.

Step-by-step explanation:

8 0
2 years ago
CAN SOMEONE HELP ME WITH THIS QUESTION!!!
earnstyle [38]

Answer:

E

Step-by-step explanation:

let a, b, c represent the number of students in 6th, 7th, 8th grade

ratio of students : teachers = 28 : 1

There are 82 teachers , so 28 × 82 = 2296 students

Then

a + b + c = 2296 , that is

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8 0
2 years ago
-5x+y=-4 in function form
DaniilM [7]
In standard form it would be y= 5x - 4
6 0
2 years ago
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
3 years ago
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