You could simplify this work by factoring "3" out of all four terms, as follows:
3(x^2 + 2x - 3) =3(0) = 0
Hold the 3 for later re-insertion. Focus on "completing the square" of x^2 + 2x - 3.
1. Take the coefficient (2) of x and halve it: 2 divided by 2 is 1
2. Square this result: 1^2 = 1
3. Add this result (1) to x^2 + 2x, holding the "-3" for later:
x^2 +2x
4 Subtract (1) from x^2 + 2x + 1: x^2 + 2x + 1 -3 -1 = 0,
or x^2 + 2x + 1 - 4 = 0
5. Simplify, remembering that x^2 + 2x + 1 is a perfect square:
(x+1)^2 - 4 = 0
We have "completed the square." We can stop here. or, we could solve for x: one way would be to factor the left side:
[(x+1)-2][(x+1)+2]=0 The solutions would then be:
x+1-2=0=> x-1=0, or x=1, and
x+1 +2 = 0 => x+3=0, or x=-3. (you were not asked to do this).
Answer:
29 is yes
and
30 is no
Step-by-step explanation:
hope this helpss
Answer:
see explanation
Step-by-step explanation:
(a)
To change a mixed number to an improper fraction
Multiply the whole number by the denominator of the fraction and add the numerator. This value is the numerator of the improper fraction while the denominator remains unchanged, that is
(2 × 13) + 12 = 26 + 12 = 38 ← numerator
2 
= 
(b)
To change an improper fraction to a mixed number
divide the numerator by the denominator, noting the remainder, which forms the numerator of the fraction in the mixed number.
= 2 remainder 9, hence
= 2 
Hiya. I'm going to rewrite the second equation.
By subtracting 5x by both sides, I'll be able to have y by itself:
-y=-5x+13
I'm going to then divide both sides by -1 to get:
y=5x-13.
Then, I'm going to plug that equation into the first equation
3x+2(5x-13)=39
Factor:
3x+10x-26=39
Combine like terms:
13x=65
Divide both sides by 13 to get x by itself to get x=5
Plug this back into the equation of y=5x-13
y=5(5)-13 to get y=12
Answer: 1/x + 7
Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)
G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7
