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3 years ago

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The roof of Mr. Thompson’s house is blank feet high to climb on top of his house healing a 13 foot ladder against the roof of hi

s house in place is the base of the latter 5 feet from the house

1 answer:

Andrews [41]3 years ago

4 0

Okay, what's the question!

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Biology if one honeybee makes 1/12 teaspoons of honey during its life time how many homey bees do you need to make1/2 tea spoons

Korolek [52]

Answer:

(1/2) / (1/12)

(1/2) * (12/1) = 12/2 = 6

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3 years ago

Whats the equation help pls.

garik1379 [7]

Answer:

One bottle cost 0.41 cents

Step-by-step explanation:

5.89 - 3.43 = 2.46

2.46 divided by 6 = 0.41

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3 years ago

Help me for 3???????

Alika [10]

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3 years ago

Read 2 more answers

Solve for x. <br><br> Brainlest for anyone who helps!! <br><br> thanks you

gavmur [86]

<h3>Answer: C) 0</h3>

================================================

Explanation:

If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.

(VS + UT)/2 = FE

(29 + x+17)/2 = 23 ... plug in given info; isolate x

(x+46)/2 = 23

x+46 = 23*2 ... multiply both sides by 2

x+46 = 46

x = 46-46 ... subtract 46 from both sides

<h3>x = 0</h3>

6 0

3 years ago

Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet

Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

$f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\$

Take the second derivative of the function, to check if it will given a minimum perimeter

$\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)$

Determine the critical points of the first derivative;

df/dw = 0

$\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m$

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0

3 years ago