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vladimir1956 [14]
3 years ago
5

Find the limit of the function by using direct substitution lim (x^2+8x-2) x-> 2

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

lim_{x \to 2} x^2 +8x -2

And using the properties of limit we got:

lim_{x \to 2} x^2 +8 \lim_{x \to 2} x - lim_{x \to 2} 2

And replacing we got:

2^2 + 8 (2) -2 = 4 +16-2 =18

Step-by-step explanation:

For this case we want to find this limit:

lim_{x \to 2} x^2 +8x -2

And using the properties of limit we got:

lim_{x \to 2} x^2 +8 \lim_{x \to 2} x - lim_{x \to 2} 2

And replacing we got:

2^2 + 8 (2) -2 = 4 +16-2 =18

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