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deff fn [24]
3 years ago
10

Figure ABCD is a parallelogram.

Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

ANSWER IS 44 UNITS

Step-by-step explanation:

EDGE 2021

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If F (x) =8+11 X-3X², find<br> a. What is F (5)? <br> b. What is F (x + b)? <br> c. What is F (-3)?
stepladder [879]

Answer:

a) -12

b) 8+11x+11b-3x^2-3b^2-6xb

c)-52

Step-by-step explanation:

in a) we have to substitute the value of x with 5

in b) we substitute the value of x with (x+b) and then simplify

in c) just have to substitute x with -3

5 0
2 years ago
Emily, Andrew, and Isaiah had a challenge to see who could bike the farthest in one day. Emily biked 13 miles, Andrew biked 4 ti
mario62 [17]

Answer:

Andrew biked 208 miles.

6 0
3 years ago
What is the measure of
posledela
The triangle is isosceles so m∠A and m∠C are the same. 

So to find ∠B, we do 74 + 74 + b = 180

148 + b = 180
b = 180 - 148
b = 32

Answer B is the right choice. 
3 0
3 years ago
1.) Find all the factors of 54.
jonny [76]

QUESTION 1.

The factors of 54  are all natural numbers that can divide 54 exactly.

The factors of 54 are: {1,2,3,6,9,18,27,54}

QUESTION 2

The prime factors of 54 are factors of 54 that are prime numbers.

The prime factors of 54 are {2,3}.

Product of prime factors of 54 is 2\times 3^3

QUESTION 3

All the factors of 60 are all positive integers that divide exactly into 60.

The factors of 60 are {1,2,3,4,5,6,10,12,15,20,30,60}

QUESTION 4

The prime factors of 60 are factors of 60 that are prime numbers.

The prime factors of 60 are {2,3,5}

The prime factorization of 60 is 2^2\times 3\times 5.

QUESTION 5

The factors of 30 are {1,2,3,5,6,10,15,30}

The different ways she can put the beads into the boxes are

1\times 30,

All 30 beads into one box or 1 bead in 30 boxes.

2\times 15,

2 beads each into 15 boxes or 15 beads each into 2 boxes

3\times 10,

3 beads each into 10 boxes or 10 beads each into 3 boxes

5\times 6,

6 beads each into 5 boxes or 5 beads each into 6 boxes

5 0
4 years ago
Limit   
STatiana [176]

Rationalize the numerator:

\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}

This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
4 years ago
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