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BARSIC [14]
2 years ago
10

Use any method to multiply (3a + 2b - c)(a - b + 2c).

Mathematics
1 answer:
Rom4ik [11]2 years ago
6 0

Answer:

3a2_2b2-2c2+ab+5ac-5bc

(3a+2b-c)(a-b+2c)

(6a2-4b2-c2)(-ab+4c2)

-6ab3+24ac4+4ab2-16bc2+abc2-4c3

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Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

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Over the interval [1, 3], the local minimum is 0

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Over the interval [1, 4], the local maximum is 0.

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