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cupoosta [38]
3 years ago
9

The current going through a car starter is 210 a if the battery maintains 12 V across the motor how much electrical energy is de

livered to the starter in 10.0 s?
Physics
1 answer:
polet [3.4K]3 years ago
3 0

Answer:

..................................,

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The cause of a fire in a computer is described as an incorrectly wired circuit.
Vikentia [17]

Hey there,

The answer to your question is:

Option A

A) The wiring contained a short circuit, so the reduced resistance caused an increase in current.

- Ari -

8 0
3 years ago
An object (mass 12.5 kg) slides on a frictionless surface at 1.32 m/s. How much work must be done to bring the object to rest
mote1985 [20]

Answer:

10.89 J.

Explanation:

The following data were obtained from the question:

Mass (m) = 12.5 kg

Velocity (v) = 1.32 m/s

Work done =?

To obtain the workdone, we shall determine the kinetic energy of the object since work and energy has the same unit of measurement. This is illustrated below:

Mass (m) = 12.5 kg

Velocity (v) = 1.32 m/s

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 12.5 × 1.32²

K.E = 6.25 × 1.7424

K.E = 10.89 J

The kinetic energy of the object is 10.89 J. Hence, the workdone in bringing the object to rest is 10.89 J.

8 0
3 years ago
What are cirrus.cirrostratus. And cirrocumulus clouds made up of
Irina-Kira [14]
<span><span>1.       </span>All clouds are made up of tiny ice crystals or small water droplets that form together with a dust on the atmosphere.
Cirrus, cirrostratus and cirrocumulus are made up of ice crystals. It forms when the water vapor goes condensation at high altitudes in where the pressure on the atmosphere reaches the point from 600 mbar at 4000 meter above the sea level up to 200mbar at 12 000m above sea level. These clouds form thunderstorms, cyclones and contrails (a manmade cloud).</span> <span>

</span>



3 0
4 years ago
An object is thrown downward with an ini-
aniked [119]

Answer:

69

Explanation:

8 0
4 years ago
Four point charges are individually brought from infinity and placed at the corners of a square. Each charge has the identical v
Brut [27]

To solve this problem we will apply the concept of voltage given by Coulomb's laws. From there we will define the charges and the distance, and we will obtain the total value of the potential difference in the system.

The length of diagonal is given as

l = 2a

The distance of the center of the square from each of the corners is

r = \frac{2a}{2}= a

The potential electric at the center due to each cornet charge is

V_1 = \frac{kQ_1}{r_1}

V_2 = \frac{kQ_2}{r_2}

V_3 = \frac{kQ_3}{r_3}

V_4 = \frac{kQ_4}{r_4}

The total electric potential at the center of the given square is

V = V_1+V_2+V_3+V_4

V = \frac{kQ_1}{r_1}+ \frac{kQ_2}{r_2}+\frac{kQ_3}{r_3}+\frac{kQ_4}{r_4}

Al the charges are equal, and the distance are equal to a, then

V = \frac{kQ}{a}+ \frac{kQ}{a}+\frac{kQ}{a}+\frac{kQ}{a}

V = \frac{4kQ}{a}

Therefore the correct option is E.

3 0
4 years ago
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