Answer:
hello attached below is the detailed solution
answer : In |x+1| + [2/(x+1)] + [1/(1+x)^2] - [y^2/2(1+x)^2] = 5/2
Step-by-step explanation:
Given
(x^2 + y^2 - 3) dx = ( y + xy ) dy, y(0) = 1
solving the given initial-value problem
Answer:
5a^4+a^2b−6b^2
Step-by-step explanation:
1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.
5a^4+6a^2b−5ba^2−6b^2
2. Collect like terms.
5a^4+(6a^2b−5a^2b)−6b^2
3. Simplify.
5a^4+a^2b−6b^2
Y = mx + b
slope(m) = 5
(6,2)...x = 6 and y = 2
sub and find b, the y int
2 = 5(6) + b
2 = 30 + b
2 - 30 = b
-28 = b
so the equation for this line is : y = 5x - 28
y = 5x - 28.......when y = -3
-3 = 5x - 28
-3 + 28 = 5x
25 = 5x
25/5 = x
5 = x <==== ur x coordinate
Answer:
they intersect at a right angle
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
