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zhannawk [14.2K]
2 years ago
7

Which equation can be used to find AB?

Mathematics
2 answers:
Tomtit [17]2 years ago
7 0
Dhidhdjdkdjdndjskdkndndkdjdndn
kogti [31]2 years ago
5 0

Answer:

cos 42 = 10 / AB

Step-by-step explanation:

Since this is a right angle, we can use trig functions

cos theta = adjacent / hypotenuse

cos 42 = 10 / AB

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Kim wrote the number 11. Use mental math to tell what number has ??
Eduardwww [97]

2 more 10s then 11 is 31

1 more 10s then 11 is 21

3 more 10s then 11 is 41.

basic math :)

3 0
3 years ago
Read 2 more answers
-3x+2-5x-7=4x+2 what is the first step solve this<br> equation?
Triss [41]

Answer: x = -0.58

Step-by-step explanation:

-3x+2-5x-7=4x+2

First step, collect like terms

-3x -5x-4x = 2-2+7

-12x = 7

x = 7/-12

x = -0.58

5 0
3 years ago
You rent a bicycle for $10 plus $2 per hour. Which type of equation is most suitable for modeling the cost of renting a bicycle?
dexar [7]

Answer:

When you rent a bicycle think about the time first.

Step-by-step explanation:

Bike it self is 10$

Time is 2$ per hour

2x(10)


6 0
3 years ago
Pls help me with this question and explain how you got the answer!!!!!
Luba_88 [7]

Answer:

-87

Step-by-step explanation:

So, first to find <em>x</em> you need to subtract 121 from 180. You do this because both the angle which measures 121 degrees and <em>x</em> lie on the same line, and since a line has an angle measure of 180, you do 180-121 to find <em>x</em>. The same thing can be done for <em>y</em>. Since the angle measure of 34 degrees and y lie on the same line you can calculate 180-34 to get <em>y. </em>So, let's do that.

180-121=x

59=x

180-34=y

146=y

Once you've done that you can easily subtract the two and get your answer.

x-y

substitute the answer for the variables and get

59-146

and then your answer is

-87

4 0
2 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
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