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mel-nik [20]
3 years ago
10

Find the product (a^2-b)(5a^2+6b)

Mathematics
1 answer:
Pie3 years ago
7 0

Answer:

5a^​4​​+a^​2​​b−6b​^2​​

Step-by-step explanation:

1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

5a^4+6a^2b−5ba^2−6b^2

2. Collect like terms.

5a^4+(6a^2b−5a^2b)−6b^2

3. Simplify.

5a^4+a^2b−6b^2

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6w + 2(4w - 7) simplified​
Gemiola [76]

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14

8 0
3 years ago
Read 2 more answers
A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.
sesenic [268]

Answer:

f(x) = 54(two-thirds) Superscript x minus 1

Step-by-step explanation:

Given that:

First peak : 36 / 54=2/3

Second peak : 24 / 36 = 2/3

The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height

Modeling this using geometric progression :

An=a1r^(n-1)

An = nth term of a geometric progression

a1=first term

r=common ratio = 2/3

n = nth term

a1=54

Substituting into the above formular :

An=54(2/3)^(n-1)

4 0
2 years ago
Read 2 more answers
What percent is 608 million of 845 million
boyakko [2]
In order to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%. 

Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%

The million doesn't matter.
5 0
3 years ago
Please help.. thank you for your assistance :)
ludmilkaskok [199]

Answer:

the slope is 1 so D

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
DedPeter [7]
Using polynomial long division, we get
         
         3x^3+6x^2+11x
         _____________
(x+2) | 3x^4-x^2+cx-2
          -(3x^4+6x^3)
          ____________
             6x^3-x^2+cx-2
          - (6x^3+12x^2)
         _____________
        11x^2+cx-2
      -(11x^2+22x) 
       __________
        (22+c)x-2. 

If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
4 0
3 years ago
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