1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh
the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given
so:
a=1/2(24)(24)
a=(12)(24)
a=288 sq. inches
since there are two triangles, you would multiply the area by 2
a=2(288)
a=576 sq. inches
now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.
a=576-(lw)
a=576- (10)(10)
a=576-100
a=476 sq. inches
that is your answer
Step-by-step explanation:
13×4/9=52/9
answer as improper fraction is 52/9
Answer:
3 * 8^(x/2)
Step-by-step explanation:
The third answer choice is the correct one.
Here's how:
3squareroot of 8^x = 3√(8^x) = 3*(8^x)^(1/2) = 3 * 8^(x/2)
Answer:
67
Step-by-step explanation: Given the quadratic equation $z^2 + bz + c = 0$, Vieta's formulas tell us the sum of the roots is $-b$, and the product of the roots is $c$. Thus,
\[-b = (-7 + 2i) + (-7 - 2i) = -14,\]so $b = 14.$
Also,
\[c = (-7 + 2i)(-7 - 2i) = (-7)^2 - (2i)^2 = 49 + 4 = 53.\]Therefore, we have $b+c = \boxed{67}$.
There are many other solutions to this problem. You might have started with the factored form $(z - (-7 + 2i))(z - (-7 - 2i)),$ or even thought about the quadratic formula.
This is the aops answer :)
549 ÷ 67 = 8.194029851
Hope this helps :)
