Answer:710.375
Step-by-step explanation:
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
10.75
11.50
11.80
12.55
13.30
14.05
14.80
15.55
(x, y) = (-3, 4) hope this helps!
Answer: 
Step-by-step explanation:
1. You have the following information:
- The lenght of 
is 2 centimeters.
- The angle m∠S=80°.
- Cos80°=0.17
2. Therefore, you can calculate the lenght of the segment 
as following:
3. Substitute values and solve for :
4. To the nearest tenth:
