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Andreas93 [3]
2 years ago
9

Please help me my eyes and brain are tired​

Mathematics
1 answer:
BaLLatris [955]2 years ago
4 0

Answer:

Step-by-step explanation:

1. 3/4  color in 6

2. 7/8  color in 7

3. 1/4 color in 2

4. 7/8 color in 7

5. 1/8 color in 1

bottom of page:

1. 1  1/3

2. 2/3

3. 1  1/20

4. 1

5. 3/4

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In parallelogram FGHJ if m∡ GHJ=55˚ find m∡FGH
hodyreva [135]

Answer:

∠ FGH = 125°

Step-by-step explanation:

The consecutive angles in a parallelogram are supplementary, then

∠ FGH + ∠ GHJ = 180° , that is

∠ FGH  + 55° = 180° ( subtract 55° from both sides )

∠ FGH = 125°

4 0
3 years ago
Read 2 more answers
What is the answer to this problem
Rudik [331]

You can 14 rows of 5 chairs, which also means you can do 5 rows of 14. Or 7 rows of 10 or 10 rows of seven. That's all I'm getting that doesn't exceed the 20 row limit.

8 0
3 years ago
You go to a restaurant with 3 friends the total bill is 90 you pay 6% tax and add 20% tip what do you pay
pshichka [43]
$90 ×.06=5.40
$95.40×.20=19.08
95.40+19.08=114.48
114.48/3=38.16
Each person pays 38.16
check your work 38.16×3=$114.48

You pay $38.16 for your bill unless your friends stiff you.
3 0
3 years ago
The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
jeyben [28]

Answer:

The period of Y increases by a factor of k^ {3/2} with respect to the period of X

Step-by-step explanation:

The equation T ^ 2 = a ^ 3 shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?  

For the planet Y:  

T_y ^ 2 = a_y ^ 3

For planet X:  

T_x ^ 2 = a_x ^ 3

To know the factor of aumeto we compared T_x with T_y

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:  

a_y ^ 3 = (a_xk) ^ 3

So

\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x

Then, the period of Y increases by a factor of k^ {3/2} with respect to the period of X



4 0
3 years ago
Yasmine is serving ice cream with the birthday cake at her party she has purchased 7 1/2 pints of ice cream she will serve 3/4 o
vlada-n [284]
7 1/2 is 7.5 and 3/4 is .75, so 7.5 divided by .75 is 10. 
8 0
3 years ago
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