Answer:
sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21
Step-by-step explanation:
During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.
Answer:
Figure B would be a transformation down.
Figure C would be a reflection.
Figure D would be a rotation of 180°.
To solve the question we proceed as follows:
Distance is the integral of the velocity. Thus given:
v(t)=3.5t+0.25t^2
d(t)=1.75t^2+0.08333t^3.....i
v(t)=1.2t+0.03t^2
d(t)=0.6t^2+0.01t^3.......ii
From equation i and ii, we conclude that using strategy i will cover greater distance