Answer:
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Step-by-step explanation:
u cant report me bc it’s against guidelines to use this for exams or timed tests
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
X + x + 10 + x + 20 + x + 30 = 84.
4x + 60 = 84.
84 − 60 = 24
4x = 24.
24 / 4 = 6 = x.
Answer:
Day One: 6 fish
Day Two: 16 fish
Day Three: 26 fish
Day Four: 36 fish
Answer:
The slope of the a straight line is given by the ratio of the Rise to the Run
of the line. The rise between the given points is zero.
The slope of the line that passes through the points (4, 10) and (1, 10) is zero.
Step-by-step explanation:
The given points are; (4, 10) and (1, 10)
The slope of a line, m, is given by the following formula;
Where;
(x₁, y₁) = (4, 10) and (x₂. y₂) = (1, 10), we get;
The slope of the line that passes through the points (4, 10) and (1, 10) is 0.
The group of those shapes are parallelograms
