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3 years ago

4 How many moles CH, are needed to produce 50 moles of CO2?

Chemistry

1 answer:

exis [7]3 years ago

3 0

Answer:

50 mol CH₄

Explanation:

The question is incomplete so I looked it up online.

How many moles CH₄, are needed to produce 50 moles of CO₂?

Step 1: Write the balanced equation for the complete combustion of methane

CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CH₄ to CO₂ is 1:1.

Step 3: Calculate the number of moles of CH₄ needed to produce 50 moles of CO₂

We will use the previously established molar ratio.

50 mol CO₂ × 1 mol CH₄/1 mol CO₂ = 50 mol CH₄

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4 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago

Consider the following data for five hypothetical elements: Q, W, X, Y, and Z. Rank the elements from most reactive to least rea

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Answer:

Y Q W Z X

Explanations:

The most reactive element is the element that will displace an element from it compound . The most reactive element will replace the less reactive element in it compound.

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Since the reaction occurs the element Y which is more reactive displaced element Q from it compound.

Q+W+ Reaction occurs

The reaction occurs, that means element Q replaces element w from it compound. Element Q is therefore more reactive than element W.

W+Z+ Reaction occurs

The reaction also occurs . This is an indication that element W replaces element Z in it compound. This means element W is very reactive than element Z.

X+Z+ No reaction

There is no reaction here. This is an indication that element X is less reactive than element Z. This is why element X can't displace element Y in it compound.

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3 years ago

To find the Ce4+ content in a solid sample, 4.3718 g of the solid sample were dissolved and treated with excess iodate to precip

gulaghasi [49]

Answer:

3.43 %

Explanation:

We need to calculate first the number of moles of CeO2 produced in the combustion. Given its formula we know how many moles of Ce atom are present. From there calculate the mass this number of moles this represent and then one can calculate the percentage.

0.1848 g CeO2 x 1 mol CeO2/172.114g = 0.00107 mol CeO2

0.00107 mol CeO2 x 1 mol Ce/ 1 mol CeO2 = 0.00107 mol Ce

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0.150 g Ce/ 4.3718 g sample x 100 = 3.43 %

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3 years ago

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Explanation :

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