<span>Fe2O3 + 3CO --> 2Fe + 3CO2
</span><span>
m(Fe2O3)=213 g
m(CO)=140 g
</span>_______________
<span>n(Fe2O3)=?
m(Fe)=?
n(Fe2O3)=?
n(CO)=?
n(CO2)=?
</span>
<span>n(Fe2O3)=m(Fe2O3) / M(Fe2O3)
n(Fe2O3)= 213 g / 159,7 gmol-1 = 1,33 mol
</span>
<span>n(CO)= m(CO) / M(CO)
n(CO)= 140 g / 28,01 gmol-1 = 4,99 mol</span>
The solution with the lowest pH would mean that it is an acid, specifically a strong acid which completely dissociates into ions in aqueous solution. Among the choices listed above, I think the correct answer is option D. It is nitric acid that will have the lowest pH because it is the only strong acid in the group
Answer:
D) Previous models
Got it right on USTestPrep
Answer: orderly arrangement of particles
Explanation:
In a crystaline solid, the particles that compose the solid are arranged or packed in an orderly manner to form a three dimensional crystal lattice with a defined structure. Sodium chloride is a crystaline solid.
In an amorphous solid, the particles that compose the solid aren't arranged in an orderly manner hence the solid tends to be brittle, e.g glass
Answer:
319.15^{o}C[/tex]
Explanation:
When all other variables are constant, we are allowed to use the formula
![\frac{T_{2} }{V_{2} } = \frac{T_{1} }{V_{1} } \\Which can be rewritten as T_{2} = \frac{T_{1} V_{2} }{V_{1} }if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to KelvinNow to calculate T2[tex]T_{2}= \frac{296.15K*3.38.10^{3}L }{1.69.10^{3}L }= 592.3K](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B2%7D%20%7D%7BV_%7B2%7D%20%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20%7D%7BV_%7B1%7D%20%7D%20%5C%5C%3C%2Fp%3E%3Cp%3EWhich%20can%20be%20rewritten%20as%20T_%7B2%7D%20%3D%20%5Cfrac%7BT_%7B1%7D%20V_%7B2%7D%20%7D%7BV_%7B1%7D%20%7D%3C%2Fp%3E%3Cp%3Eif%20you%20make%20T2%20the%20subject%20of%20the%20formula.%20This%20formula%20is%20true%20only%20if%20temperature%20is%20in%20Kelvin%20not%20degrees%20Celsius%20so%20T1%20must%20be%20converted%20to%20Kelvin%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3ENow%20to%20calculate%20T2%3C%2Fp%3E%3Cp%3E%5Btex%5DT_%7B2%7D%3D%20%5Cfrac%7B296.15K%2A3.38.10%5E%7B3%7DL%20%7D%7B1.69.10%5E%7B3%7DL%20%7D%3D%20592.3K)
= 
