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snow_lady [41]
3 years ago
7

I will give brainiest to whoever answers correctly.

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer:

x= 1.25    y = 1.75

Step-by-step explanation:

8/5 = 10/ (5+x)

Cross multiplucation

 8(5+x) = 5x10

40 + 8x = 50

8x = 10

x = 1.25

          8/7  =  10/ (7+y)

           Cross multiplication

        8(7+y) = 10x7

          56+8y = 70

          8y =  14

             y = 1.75

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A line passes through the point (–7, 5) and has a slope of 1/2. Which is another point that the line passes through?
Andrej [43]
The answer to this question is (9,13). Here's how:
First thing you need to do is find the equation. You have a coordinate point and the slope. Remember a linear equation or formula is y=mx+b (m= slope and b= y-intercept)

So let's input the slope into the equation:
y=1/2x+b or y=0.5x+b
Notice how there is no b yet? That's because you need to find it. Good thing you have the coordinate points, so replace x and y with it. ( (x,y) = ( -7, 5) )

5=0.5(-7)+b
5= -3.5+b
+3.5 +3.5
b= 8.5
The equation is now y=0.5x+8.5 and with that equation you can now input it in a calculator to find which of the following coordinate points lies on. Or you can just input those points into the calculator. Which I did because I love to show my work. I have a picture of the work included and I really do hope I helped you. If not, message me. I'll be glad you to help you!

7 0
3 years ago
Determine the equation of the tangent line to the given path at the specified value of t. (sin(7t), cos(7t), 2t9/2); t=1
Reptile [31]

Answer:

P(t) = {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

Step-by-step explanation:

The equation of the tangent line to the given path at the specified value of t is expressed as;

P(t) = f(t0) + f'(t0)(t - t0)

f(t0) = (sin(7t), cos(7t), 2t^9/2)

at t0 = 1;

f(t0) = {sin7(1), cos7(1), 2(1)^9/2}

f(t0) = {sin7, cos7, 2}

f'(t0) = (7cos7t, -7sin7t, 9/2{2t^9/2-1}

f'(t0) = (7cos7t, -7sin7t, 9t^7/2}

If t0 = 1

f'(1) = (7cos7(1), -7sin7(1), 9(1)^7/2)

f'(1) =(7cos7, -7sin7, 9)

Substituting the given function into the tangent equation will give:

P(t) = f(t0) + f'(t0)(t - t0)

P(t)= {sin7, cos7, 2} + (7cos7, -7sin7, 9)(t-1)

The final expression gives the equation of the tangent line to the path.

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Answer: 8 hours

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