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Novay_Z [31]
3 years ago
8

I really need help can anyone help me?​

Mathematics
2 answers:
alex41 [277]3 years ago
8 0
The slope formula is y2-y1/x2-x1 so 5-(-1) =6 Then. 1-(-1)=2 so 6/2. =3. THE ANSWER IS 3
Andrews [41]3 years ago
7 0
The slope= 1/3 do you need me to show an explanation as well?
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What is 78% of 40?? please help me
xxTIMURxx [149]
p\%=\frac{p}{100}\\\\78\%=\frac{78}{100}=0.78\\\\therefore\\\\78\%\ of\ 40=0.78\cdot40=\boxed{31.2}
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3 years ago
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Super easy 1 question (8) just being lazy
Snezhnost [94]

is this a school qustion? if not

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6 0
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Ms. Bergstedt asked two students to come up with two different sequences. Jay created this sequence: The first term is 4 and eac
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8 0
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A fixed asset with a five-year estimated useful life and no residual value is sold at the end of the second year of its useful l
DerKrebs [107]

Answer:

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(Increase)

Step-by-step explanation:

5 0
3 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
3 years ago
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