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nydimaria [60]
3 years ago
10

Please help me For problems 8-10, find the measures of the unknown third angles.​

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

8=58.5°

9= 125°

10= 55°

Step-by-step explanation:

8.) 31.5 + 90 = 121.5 - 180 = 58.5°

9.) 25 + 30 = 55 - 180 = 125°

10.) 45 + 80 = 125 - 180 = 55°

olya-2409 [2.1K]3 years ago
3 0

Answer:

8=58.5 9=125 10=55

Step-by-step explanation:

a triangle equals 180. so by add the angles we do know than subtracting the answer from 180. is our final answer

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1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA


secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A


sin2A.2.sin2A/cos2A


tg2A.2.sin2A


6 0
3 years ago
-<br><img src="https://tex.z-dn.net/?f=%20-%203%5Cpi%20%2B%20w%20%3D%202%5Cpi" id="TexFormula1" title=" - 3\pi + w = 2\pi" alt="
pantera1 [17]

Isolate the w. Note the equal sign. What you do to one side, you do to the other.

Add 3π to both sides

- 3π (+3π) + w = 2π (+3π)

w = 2π + (3π)

w = 5π

w = 5π is your answer

hope this helps

4 0
3 years ago
1. The county fair charges $1.25 per Sicket for the rides. Jermaine bought 25 tickets for the rides and spent a
schepotkina [342]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Find the measure of
sergij07 [2.7K]

Answer:

∠ ABC ≈ 137.9°

Step-by-step explanation:

Using the Cosine rule in Δ ABC

cos B = \frac{a^2+c^2-b^2}{2ac}

with a = 89, b = 144, c = 65

cos B = \frac{89^2+65^2-144^2}{2(89)(65)} = \frac{7921+4225-20736}{11570} = \frac{-8590}{11570} , thus

B = cos^{-1} ( - \frac{8590}{11570} ) ≈ 137.9° ( to the nearest tenth )

4 0
4 years ago
The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0
3 years ago
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