Ask question

Ask question

All categories

3 years ago

6

Phoebe and Gemma deliver newspapers. Phoebe works for 5 hours and Gemma for 4 hours. The total pay is £27. How much should Gemma

get?

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

12$ is the amount Gemma would get.

Step-by-step explanation:

27$ divided by 9 hours is 3$ per hour, aka the unit rate. Since Gemma worked 4 hours, we do 3$x4 and we get 12$

You might be interested in

Write 8x+4y=32 in slope intercept form

Dennis_Churaev [7]

Answer:

y=2x-8

Step-by-step explanation:

7 0

3 years ago

A computer chess game and a human chess champion are evenly matched. They play ten games. Find probabilities for the following e

AleksAgata [21]

Answer:

(a) The probability that each of them win five games is 0.2461.

(b) The probability that the computer wins seven games is 0.1172.

(c) The probability that the human wins at least 7 games is 0.1711.

Step-by-step explanation:

Let the random variable <em>X</em> = the human wins a chess game.

The probability that the human wins a game is, P (X) = <em>p</em> = 0.50.

The number of games played by the computer and the human is, <em>n </em>= 10.

The random variable $X\sim Bin(n = 10,p=0.50)$

The probability distribution of the Binomial random variable <em>X</em> is:

$P (X=x)={n\choose x}p^{x}(1-p)^{n-x}={10\choose x}(0.50)^{x}(1-0.50)^{10-x}$

(a)

If both the computer and the human wins five games each then the probability of the human winning 5 games is:

$P (X=5)={10\choose 5}(0.50)^{5}(1-0.50)^{10-5}\\=252\times 0.03125\times0.03125\\=0.246094\\\approx 0.2461$

Thus, the probability that each of them win five games is 0.2461.

(b)

If the computer wins 7 games then the number of games won by the human is, 10 - 7 = 3.

P (Computer winning 7 games) = P (Human winning 3 games)

The probability that the human wins 3 games is:

$P (X=3)={10\choose 3}(0.50)^{3}(1-0.50)^{10-3}\\=120\times 0.125\times0.0078125\\=0.1171875\\\approx 0.1172$

Thus, the probability that the computer wins seven games is 0.1172.

(c)

Compute the probability that the human wins at least 7 games as follows:

$P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\={10\choose 7}(0.50)^{7}(1-0.50)^{10-7}+{10\choose 8}(0.50)^{8}(1-0.50)^{10-8}\\+{10\choose 9}(0.50)^{9}(1-0.50)^{10-9}+{10\choose 10}(0.50)^{10}(1-0.50)^{10-10}\\=0.1172+0.044+0.009+0.0009\\=0.1711$

Thus, the probability that the human wins at least 7 games is 0.1711.

5 0

3 years ago

If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i

nadya68 [22]

Answer:

12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

28 - 4 = 24
39 - 3 = 36

<u>Lets find GCF of 24 and 36:</u>

24 = 2*2*2*3
36 = 2*2*3*3
GCF(24,36) = 2*2*3 = 12

The largest possible number of students is 12

7 0

3 years ago

The ratio of green food coloring 1:2 if we use 6 drops of blue how many drops will we need math

Hatshy [7]

Of green food coloring to what ?

3 0

4 years ago

Read 2 more answers

Evaluate 6+3b if b=7

Pavlova-9 [17]

27. Replace b with 7, making 6 + 3(7). The 3 and parentheses of 7 hint multiplication, so you multiply to make 21, then add 6 relating back to PEMDAS to teach you the correct order to solve the problem.

6 0

4 years ago

Read 2 more answers