Answer:
It is C.
Step-by-step explanation:
You divided 6.57 by 3
and 3 by 3
3 by 3 = 1
6.57 = 2.19
3 so for every 1 pound it costs $2.19
Given that the cube has a length given by 4/5n inches, the volume will be given by:
volume=length*width*height
but since it's a cube:
length=width=height
volume=(4/5n)^3
=64/125n^3 cubic inches
Question Completion:
SubID Memory1 Memory2
1 71 78
2 75 75
3 77 82
4 90 91
5 72 90
6 79 81
7 84 75
8 75 86
9 85 92
10 75 77
11 72 92
12 76 87
13 77 93
14 90 94
15 84 78
16 73 92
17 75 85
18 87 86
19 75 95
20 70 94
21 72 75
22 90 84
23 81 94
24 87 82
25 90 82
26 87 79
27 78 94
28 78 79
29 70 82
30 81 80
31 80 78
32 90 87
33 83 90
34 81 85
35 73 88
36 82 82
37 84 94
38 85 86
39 77 94
40 82 83
Answer:
Since the mean of Memory1 (reciting method) (79.8) is smaller than the mean of Memory2 (imagery method) (85.5), we can conclude that there is a significant difference in memory performance between the reciting method and the imagery method.
Step-by-step explanation:
a) Data and Calculations:
SubID Memory1 Memory2
1 71 78
2 75 75
3 77 82
4 90 91
5 72 90
6 79 81
7 84 75
8 75 86
9 85 92
10 75 77
11 72 92
12 76 87
13 77 93
14 90 94
15 84 78
16 73 92
17 75 85
18 87 86
19 75 95
20 70 94
21 72 75
22 90 84
23 81 94
24 87 82
25 90 82
26 87 79
27 78 94
28 78 79
29 70 82
30 81 80
31 80 78
32 90 87
33 83 90
34 81 85
35 73 88
36 82 82
37 84 94
38 85 86
39 77 94
40 82 83
Total 3,193 3,421
Mean 79.8 85.5
Difference in means = 5.7 (85.5 - 79.8)
If this is square So,
area of the shaded region = area of square - area of circle r=1/2 × 7 = 3.5
= (S×S) - (Pi × r^2)
= (7×7) - (3.14 × (3.5)^2 ) = 10.535 cm
There are 4 positions in the string that each have 25 choices (any letter in the English alphabet except A) and the other positions are filled with A, so there are 25⁴ possible strings containing exactly 7 A's.
Overall, there are 26¹¹ possible strings of length 11.
Then the probability of randomly generating a string containing exactly 7 A's is
25⁴ / 26¹¹ ≈ 0.000000000106427
