The equation r = square root of theta can be translated into a semi-circle through the simplification to r^2 = theta. When theta is 0, r is zero. When r is -3pi/2, r2 is equal to 9/4 pi^2. The area of the semi-circle is equal to pi r^2 /2. Hence the area is equal to 34.88 units^2
Answer:
x (6v+7) x (3v+2)
Step-by-step explanation:
18v^9 + 33v^8 +14v^7
Factor out v^7 from the expression
v^7 x (18v^2+33v+14)
write 33v as a sum
v^7 x (18v^2+21v+12v+14) *like this 21v+12v
Factor out 3v from the expression
v^7 x (3v x (6v+7)+12v+14)
Factor out 2 from the expression
c^7 x (3v x (6v+7)+2(6v+7)
Factor out 6v+7 from the expression
v^7 x (6v+7) x (3v+2)
Find a common multiplier between both which would be 4. then divide each term by 4. all you have left stays in the parenthesees.
4 (2x+5)
A = 1/4 * (pi) * d^2
A = 1/4 * (pi) * 8^2
A = 1/4 * (pi) * 64
A = 1/4(64) * (pi)
A = 64/4 * (pi)
A = 16 (pi) in^2
Your answer is 16 pi in^2
~Silver
Answer:
x=2, y=3
Step-by-step explanation:
This is a <u>system of equations</u>.
To solve a system of equations, we use the substitution method.
We can plug in the first equation,
, into the value for <em>x</em> in the second equation. Now, the second equation looks like this:

We simplify and solve for <em>y</em>:
→ 
→ 
→ 
Now, we plug in the value for <em>y</em>, which is 3, into either equation. I will just use the first equation:
→ 
→ 
Let me know if my explanation is unclear.