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3 years ago

11

Identify the Domain and Range of the graph below: Domain: Range:

1 answer:

Nuetrik [128]3 years ago

5 0

Domain is all real numbers
Range i forgot I’m sorry

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Which expression shows the results of applying the distributive property to 3 (1/5x- 1/7)

marshall27 [118]

The first option: (3/5)x - 3/6

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3 men painting a house take 7's

iVinArrow [24]

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21 days

Step-by-step explanation:

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3 years ago

How can you tell if a system of equations has infinite solutions?

kirill [66]

To tell if an equation has infinite solutions, the equation will be equal to each other.

For example,

x = x
x + 1 = x + 1
x - y = x - y

And so on...

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3 years ago

A ladder reaches the top of a 20 foot building. the ladder is 4.5 feet away from the building. how long is the ladder?

KATRIN_1 [288]

Answer:

C

Step-by-step explanation:

do that with pithagoras:

20² + 4,5² = x²

400 + 20,25 = x²

420,25 = x²

x = $\sqrt{420,25}$

x ~ 20,5

Letter C: 20,5 feet

4 0

3 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

3 years ago