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Mariana [72]
2 years ago
12

Lamp Initial Price ($) Energy Cost per Year ($)

Mathematics
1 answer:
mash [69]2 years ago
3 0

Answer:

The answer is B, put in the figures and solve

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Think about all of the ways in which a circle and a parabola can intersect.
xeze [42]

There will be four ways a circle and a parabola can intersect because the solution of the quartic equation will be 4.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have a circle and a parabola:

As we know the standard form of a circle:

\rm (x-h)^2 +(y-k)^2=r^2

The standard form of the parabola:

\rm y = a(x-h)^2+k  

If we plug the value of y from the parabola equation in the circle equation, we get a quartic equation(4th order equation)

The solution of the quartic equation will be 4.

Thus, there will be four ways a circle and a parabola can intersect because the solution of the quartic equation will be 4.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

7 0
2 years ago
Find the slope of a line parallel to each given line. <br> 5)2x+3y=-3
Volgvan

Answer:

-2/3

Step-by-step explanation:

2x + 3y = - 3      re-arrange to y = mx+b form: slope of this line will be 'm'

y = -2/3 x -1        slope = -2/3     parallel slope is the same

7 0
1 year ago
Please help me Algebra Graph!​
Luba_88 [7]
There is no attachment to your phone question. I look forward to answer your question.
3 0
2 years ago
In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons
GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

In\:\triangle AOC \:\&\:\triangle BOD

AO \cong OB.... (given)

\angle AOC \cong\angle BOD

(vertical \: \angle s)

CO \cong OD.... (given)

\therefore \triangle AOC \:\cong\:\triangle BOD

(SAS \: postulate)

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

AC = BD

m\angle OAC = m\angle OBD

m\angle OCA = m\angle ODB

7 0
3 years ago
Solve the system algebraically. Check your work.
Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10     (1)

And 3x+2y=63x+2y=6      (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30      (3)

15x+10y=3015x+10y=30      (4)

Now subtract  (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

8 0
3 years ago
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